Summary

You searched for: inst=-104

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1

New Number: 2.54 |  AESZ: 41  |  Superseeker: 2 -104  |  Hash: a9ddeed4299f59fb9ac9f6f248383b8f  

Degree: 2

\(\theta^4-2 x(2\theta+1)^2(7\theta^2+7\theta+3)+2^{2} 3^{4} x^{2}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 6, 54, 60, -19530, ...
--> OEIS
Normalized instanton numbers (n0=1): 2, -7, -104, -588, 3300, ... ; Common denominator:...

Discriminant

\(1-56z+1296z^2\)

Local exponents

\(0\)\(\frac{ 7}{ 324}-\frac{ 1}{ 81}\sqrt{ 2}I\)\(\frac{ 7}{ 324}+\frac{ 1}{ 81}\sqrt{ 2}I\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

Hadamard product $I \ast \delta$

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2

New Number: 2.58 |  AESZ: 46  |  Superseeker: -6 -104  |  Hash: 2226ec115674e71c483ba2c0350e8adf  

Degree: 2

\(\theta^4-2 3 x(2\theta+1)^2(9\theta^2+9\theta+5)+2^{2} 3^{6} x^{2}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 30, 1782, 129900, 10463670, ...
--> OEIS
Normalized instanton numbers (n0=1): -6, -6, -104, 36, -4812, ... ; Common denominator:...

Discriminant

\((108z-1)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 108}\)\(\infty\)
\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(\frac{ 1}{ 6}\)\(1\)
\(0\)\(\frac{ 5}{ 6}\)\(1\)
\(0\)\(1\)\(\frac{ 3}{ 2}\)

Note:

Hadamard product $I \ast \iota$

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3

New Number: 5.31 |  AESZ: 212  |  Superseeker: -20/7 -104  |  Hash: f72aa947ba945355102b3fef56e0af0f  

Degree: 5

\(7^{2} \theta^4+2 7 x\left(134\theta^4+286\theta^3+234\theta^2+91\theta+14\right)-2^{2} x^{2}\left(3183\theta^4+10266\theta^3+13501\theta^2+8225\theta+1918\right)+2^{3} x^{3}\left(2588\theta^4+8400\theta^3+10256\theta^2+5649\theta+1190\right)-2^{4} 3 x^{4}\left(256\theta^4+848\theta^3+1141\theta^2+717\theta+174\right)+2^{8} 3^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -4, 64, -1408, 37216, ...
--> OEIS
Normalized instanton numbers (n0=1): -20/7, 57/4, -104, 16385/14, -110508/7, ... ; Common denominator:...

Discriminant

\((4z-1)(16z^2-44z-1)(6z-7)^2\)

Local exponents

\(\frac{ 11}{ 8}-\frac{ 5}{ 8}\sqrt{ 5}\)\(0\)\(\frac{ 1}{ 4}\)\(\frac{ 7}{ 6}\)\(\frac{ 11}{ 8}+\frac{ 5}{ 8}\sqrt{ 5}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(1\)

Note:

There is a second MUM-point corresponding to Operator AESZ 117 /5.515.

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4

New Number: 8.3 |  AESZ: 105  |  Superseeker: 8 -104  |  Hash: 7b27135451cf2016217211c633b7ab83  

Degree: 8

\(\theta^4-2^{2} x(3\theta^2+3\theta+1)(7\theta^2+7\theta+2)+2^{5} 3 x^{2}\left(15\theta^4+28\theta^3+39\theta^2+22\theta+4\right)-2^{10} x^{3}\left(21\theta^4-126\theta^3-386\theta^2-291\theta-76\right)+2^{14} x^{4}\left(37\theta^4+74\theta^3+50\theta^2+13\theta+6\right)+2^{18} x^{5}\left(21\theta^4+210\theta^3+118\theta^2-19\theta-24\right)+2^{21} 3 x^{6}\left(15\theta^4+32\theta^3+45\theta^2+32\theta+8\right)+2^{26} x^{7}(3\theta^2+3\theta+1)(7\theta^2+7\theta+2)+2^{32} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 8, 200, 6272, 233896, ...
--> OEIS
Normalized instanton numbers (n0=1): 8, 71/2, -104, 4202, 50112, ... ; Common denominator:...

Discriminant

\((8z+1)(64z-1)(4z+1)(32z-1)(1+256z^2)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(-\frac{ 1}{ 8}\)\(0-\frac{ 1}{ 16}I\)\(0\)\(0+\frac{ 1}{ 16}I\)\(\frac{ 1}{ 64}\)\(\frac{ 1}{ 32}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(3\)\(0\)\(3\)\(1\)\(1\)\(1\)
\(2\)\(2\)\(4\)\(0\)\(4\)\(2\)\(2\)\(1\)

Note:

Hadamard product $a \ast d$. This operator has a second MUM-point at infinity with the same instanton numbers.
It can be reduced to an operator of degree 4 with a single MUM-point defined over
$Q(\sqrt{-1})$.

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