Summary

You searched for: inst=-20/7

Your search produced exactly one match

1

New Number: 5.31 |  AESZ: 212  |  Superseeker: -20/7 -104  |  Hash: f72aa947ba945355102b3fef56e0af0f  

Degree: 5

\(7^{2} \theta^4+2 7 x\left(134\theta^4+286\theta^3+234\theta^2+91\theta+14\right)-2^{2} x^{2}\left(3183\theta^4+10266\theta^3+13501\theta^2+8225\theta+1918\right)+2^{3} x^{3}\left(2588\theta^4+8400\theta^3+10256\theta^2+5649\theta+1190\right)-2^{4} 3 x^{4}\left(256\theta^4+848\theta^3+1141\theta^2+717\theta+174\right)+2^{8} 3^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -4, 64, -1408, 37216, ...
--> OEIS
Normalized instanton numbers (n0=1): -20/7, 57/4, -104, 16385/14, -110508/7, ... ; Common denominator:...

Discriminant

\((4z-1)(16z^2-44z-1)(6z-7)^2\)

Local exponents

\(\frac{ 11}{ 8}-\frac{ 5}{ 8}\sqrt{ 5}\)\(0\)\(\frac{ 1}{ 4}\)\(\frac{ 7}{ 6}\)\(\frac{ 11}{ 8}+\frac{ 5}{ 8}\sqrt{ 5}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(1\)

Note:

There is a second MUM-point corresponding to Operator AESZ 117 /5.515.

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