Summary

You searched for: sol=-604/27

Your search produced exactly one match

1

New Number: 6.31 |  AESZ:  |  Superseeker: 2/3 13/3  |  Hash: fcd8db2a3ad7e58151e501b5872652df  

Degree: 6

\(3^{6} \theta^4+2 3^{5} x\left(7\theta^2+7\theta+2\right)-2^{2} 3^{4} x^{2}\left(465\theta^4+1860\theta^3+3069\theta^2+2418\theta+752\right)-3^{3} x^{3}(\theta+2)(\theta+1)(19327\theta^2+57981\theta+52674)+2^{5} 3^{2} x^{4}(17298\theta^2+69192\theta+54655)(\theta+2)^2+2^{4} 3^{2} 11 31 251 x^{5}(\theta+1)(\theta+2)(\theta+3)(\theta+4)-2^{3} 11^{2} 251^{2} x^{6}(\theta+5)(\theta+4)(\theta+2)(\theta+1)\)

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Coefficients of the holomorphic solution: 1, -4/3, 196/9, -604/27, 83956/81, ...
--> OEIS
Normalized instanton numbers (n0=1): 2/3, 5/3, 13/3, 59/3, 119, ... ; Common denominator:...

Discriminant

\(-(11z-3)(22z+3)(1004z^2+66z-9)(251z^2-33z-9)\)

Local exponents

\(-\frac{ 3}{ 22}\)\(\frac{ 33}{ 502}-\frac{ 45}{ 502}\sqrt{ 5}\)\(-\frac{ 33}{ 1004}-\frac{ 45}{ 1004}\sqrt{ 5}\)\(0\)\(-\frac{ 33}{ 1004}+\frac{ 45}{ 1004}\sqrt{ 5}\)\(\frac{ 33}{ 502}+\frac{ 45}{ 502}\sqrt{ 5}\)\(\frac{ 3}{ 11}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(2\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(4\)
\(2\)\(2\)\(2\)\(0\)\(2\)\(2\)\(2\)\(5\)

Note:

This is operator "6.31" from ...

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