Summary

You searched for: sol=92

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1

New Number: 5.67 |  AESZ: 275  |  Superseeker: 116/5 186172/5  |  Hash: f411d346afd4b8ff14b8b4c1836bae77  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(592\theta^4+1568\theta^3+1419\theta^2+635\theta+115\right)+2^{4} x^{2}\left(65536\theta^4+514048\theta^3+902816\theta^2+598400\theta+144735\right)+2^{10} x^{3}\left(106496\theta^4+122880\theta^3-594816\theta^2-794880\theta-265065\right)-2^{19} x^{4}\left(8192\theta^4+77824\theta^3+145728\theta^2+102016\theta+24527\right)-2^{26} x^{5}(8\theta+5)(8\theta+7)(8\theta+9)(8\theta+11)\)

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Coefficients of the holomorphic solution: 1, 92, 14124, 2572400, 510577900, ...
--> OEIS
Normalized instanton numbers (n0=1): 116/5, -5993/5, 186172/5, -8039756/5, 384321296/5, ... ; Common denominator:...

Discriminant

\(-(-1+64z)(256z+5)^2(256z-1)^2\)

Local exponents

\(-\frac{ 5}{ 256}\)\(0\)\(\frac{ 1}{ 256}\)\(\frac{ 1}{ 64}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 5}{ 8}\)
\(1\)\(0\)\(0\)\(1\)\(\frac{ 7}{ 8}\)
\(3\)\(0\)\(1\)\(1\)\(\frac{ 9}{ 8}\)
\(4\)\(0\)\(1\)\(2\)\(\frac{ 11}{ 8}\)

Note:

This is operator "5.67" from ...

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2

New Number: 11.9 |  AESZ:  |  Superseeker: 17/3 4127/9  |  Hash: fa7c260e6f07cef5d727e6af380a6373  

Degree: 11

\(3^{2} \theta^4-3 x\theta(20\theta^3+196\theta^2+125\theta+27)-x^{2}\left(19127\theta^4+69044\theta^3+89705\theta^2+54504\theta+13248\right)-2 x^{3}\left(285799\theta^4+1251420\theta^3+2142633\theta^2+1678248\theta+511560\right)-2^{2} x^{4}\left(2058125\theta^4+11190220\theta^3+23374875\theta^2+21658060\theta+7556504\right)-2^{3} x^{5}\left(8570685\theta^4+57030456\theta^3+140934413\theta^2+149627146\theta+57858760\right)-2^{6} x^{6}\left(5382486\theta^4+43183593\theta^3+124360784\theta^2+148979343\theta+62839586\right)-2^{7} x^{7}\left(7897671\theta^4+75745098\theta^3+252663545\theta^2+339244430\theta+154810568\right)-2^{10} x^{8}(\theta+1)(1454893\theta^3+15409953\theta^2+50286726\theta+48898444)-2^{11} x^{9}(\theta+1)(\theta+2)(227963\theta^2+3375435\theta+10342960)+2^{14} x^{10}(\theta+3)(\theta+2)(\theta+1)(48476\theta+271867)-2^{15} 3 5 13 23 x^{11}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 0, 92, 2328, 91212, ...
--> OEIS
Normalized instanton numbers (n0=1): 17/3, 257/6, 4127/9, 23827/3, 496999/3, ... ; Common denominator:...

Discriminant

\(-(5z+1)(13z+1)(6z+1)(368z^2+56z-1)(4z+1)^2(8z^2-26z-3)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(-\frac{ 1}{ 5}\)\(-\frac{ 7}{ 92}-\frac{ 3}{ 46}\sqrt{ 2}\)\(-\frac{ 1}{ 6}\)\(\frac{ 13}{ 8}-\frac{ 1}{ 8}\sqrt{ 193}\)\(-\frac{ 1}{ 13}\)\(0\)\(-\frac{ 7}{ 92}+\frac{ 3}{ 46}\sqrt{ 2}\)\(\frac{ 13}{ 8}+\frac{ 1}{ 8}\sqrt{ 193}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(2\)
\(1\)\(1\)\(1\)\(1\)\(3\)\(1\)\(0\)\(1\)\(3\)\(3\)
\(1\)\(2\)\(2\)\(2\)\(4\)\(2\)\(0\)\(2\)\(4\)\(4\)

Note:

This is operator "11.9" from ...

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3

New Number: 8.65 |  AESZ:  |  Superseeker: -24/5 -1608/5  |  Hash: 5e457fa5807a784e24220c973aeceba8  

Degree: 8

\(5^{2} \theta^4+2^{2} 5 x\left(73\theta^4+122\theta^3+96\theta^2+35\theta+5\right)-2^{4} x^{2}\left(134\theta^4+2072\theta^3+3924\theta^2+2660\theta+645\right)-2^{6} x^{3}\left(708\theta^4+672\theta^3-2898\theta^2-3750\theta-1285\right)+2^{10} x^{4}\left(110\theta^4+700\theta^3+498\theta^2-56\theta-105\right)+2^{12} x^{5}\left(61\theta^4-266\theta^3-544\theta^2-373\theta-88\right)-2^{14} x^{6}\left(86\theta^4+168\theta^3+172\theta^2+108\theta+31\right)+2^{16} x^{7}\left(32\theta^4+112\theta^3+158\theta^2+102\theta+25\right)-2^{20} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -4, 92, -2704, 95596, ...
--> OEIS
Normalized instanton numbers (n0=1): -24/5, 329/10, -1608/5, 48409/10, -455264/5, ... ; Common denominator:...

Discriminant

\(-(4z-1)(256z^3-192z^2+56z+1)(-5-16z+32z^2)^2\)

Local exponents

\(\frac{ 1}{ 4}-\frac{ 1}{ 8}\sqrt{ 14}\) ≈\(-0.016861\)\(0\)\(\frac{ 1}{ 4}\) ≈\(0.38343-0.290965I\) ≈\(0.38343+0.290965I\)\(\frac{ 1}{ 4}+\frac{ 1}{ 8}\sqrt{ 14}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)\(1\)\(3\)\(1\)
\(4\)\(2\)\(0\)\(2\)\(2\)\(2\)\(4\)\(1\)

Note:

This is operator "8.65" from ...

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