Summary

You searched for: sol=2328

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1

New Number: 11.9 |  AESZ:  |  Superseeker: 17/3 4127/9  |  Hash: fa7c260e6f07cef5d727e6af380a6373  

Degree: 11

\(3^{2} \theta^4-3 x\theta(20\theta^3+196\theta^2+125\theta+27)-x^{2}\left(19127\theta^4+69044\theta^3+89705\theta^2+54504\theta+13248\right)-2 x^{3}\left(285799\theta^4+1251420\theta^3+2142633\theta^2+1678248\theta+511560\right)-2^{2} x^{4}\left(2058125\theta^4+11190220\theta^3+23374875\theta^2+21658060\theta+7556504\right)-2^{3} x^{5}\left(8570685\theta^4+57030456\theta^3+140934413\theta^2+149627146\theta+57858760\right)-2^{6} x^{6}\left(5382486\theta^4+43183593\theta^3+124360784\theta^2+148979343\theta+62839586\right)-2^{7} x^{7}\left(7897671\theta^4+75745098\theta^3+252663545\theta^2+339244430\theta+154810568\right)-2^{10} x^{8}(\theta+1)(1454893\theta^3+15409953\theta^2+50286726\theta+48898444)-2^{11} x^{9}(\theta+1)(\theta+2)(227963\theta^2+3375435\theta+10342960)+2^{14} x^{10}(\theta+3)(\theta+2)(\theta+1)(48476\theta+271867)-2^{15} 3 5 13 23 x^{11}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 0, 92, 2328, 91212, ...
--> OEIS
Normalized instanton numbers (n0=1): 17/3, 257/6, 4127/9, 23827/3, 496999/3, ... ; Common denominator:...

Discriminant

\(-(5z+1)(13z+1)(6z+1)(368z^2+56z-1)(4z+1)^2(8z^2-26z-3)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(-\frac{ 1}{ 5}\)\(-\frac{ 7}{ 92}-\frac{ 3}{ 46}\sqrt{ 2}\)\(-\frac{ 1}{ 6}\)\(\frac{ 13}{ 8}-\frac{ 1}{ 8}\sqrt{ 193}\)\(-\frac{ 1}{ 13}\)\(0\)\(-\frac{ 7}{ 92}+\frac{ 3}{ 46}\sqrt{ 2}\)\(\frac{ 13}{ 8}+\frac{ 1}{ 8}\sqrt{ 193}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(2\)
\(1\)\(1\)\(1\)\(1\)\(3\)\(1\)\(0\)\(1\)\(3\)\(3\)
\(1\)\(2\)\(2\)\(2\)\(4\)\(2\)\(0\)\(2\)\(4\)\(4\)

Note:

This is operator "11.9" from ...

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