Summary

You searched for: sol=2572400

Your search produced exactly one match

1

New Number: 5.67 |  AESZ: 275  |  Superseeker: 116/5 186172/5  |  Hash: f411d346afd4b8ff14b8b4c1836bae77  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(592\theta^4+1568\theta^3+1419\theta^2+635\theta+115\right)+2^{4} x^{2}\left(65536\theta^4+514048\theta^3+902816\theta^2+598400\theta+144735\right)+2^{10} x^{3}\left(106496\theta^4+122880\theta^3-594816\theta^2-794880\theta-265065\right)-2^{19} x^{4}\left(8192\theta^4+77824\theta^3+145728\theta^2+102016\theta+24527\right)-2^{26} x^{5}(8\theta+5)(8\theta+7)(8\theta+9)(8\theta+11)\)

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Coefficients of the holomorphic solution: 1, 92, 14124, 2572400, 510577900, ...
--> OEIS
Normalized instanton numbers (n0=1): 116/5, -5993/5, 186172/5, -8039756/5, 384321296/5, ... ; Common denominator:...

Discriminant

\(-(-1+64z)(256z+5)^2(256z-1)^2\)

Local exponents

\(-\frac{ 5}{ 256}\)\(0\)\(\frac{ 1}{ 256}\)\(\frac{ 1}{ 64}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 5}{ 8}\)
\(1\)\(0\)\(0\)\(1\)\(\frac{ 7}{ 8}\)
\(3\)\(0\)\(1\)\(1\)\(\frac{ 9}{ 8}\)
\(4\)\(0\)\(1\)\(2\)\(\frac{ 11}{ 8}\)

Note:

This is operator "5.67" from ...

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