### Summary

You searched for: superseeker=17/7,5095/21

Your search produced exactly one match

1

New Number: 5.34 |  AESZ: 217  |  Superseeker: 17/7 5095/21  |  Hash: e8743aeac19deca699ff90aaef6b8ea7

Degree: 5

$7^{2} \theta^4+7 x\theta(-14-73\theta-118\theta^2+13\theta^3)-2^{3} 3 x^{2}\left(3378\theta^4+13446\theta^3+18869\theta^2+11158\theta+2352\right)-2^{4} 3^{3} x^{3}\left(3628\theta^4+17920\theta^3+31668\theta^2+22596\theta+5383\right)-2^{8} 3^{3} x^{4}(2\theta+1)(572\theta^3+2370\theta^2+2896\theta+1095)-2^{10} 3^{4} x^{5}(2\theta+1)(6\theta+5)(6\theta+7)(2\theta+3)$

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Coefficients of the holomorphic solution: 1, 0, 72, 720, 37800, ...
--> OEIS
Normalized instanton numbers (n0=1): 17/7, 254/7, 5095/21, 29600/7, 491991/7, ... ; Common denominator:...

#### Discriminant

$-(16z+1)(27z+1)(48z-1)(7+24z)^2$

#### Local exponents

$-\frac{ 7}{ 24}$$-\frac{ 1}{ 16}$$-\frac{ 1}{ 27}$$0$$\frac{ 1}{ 48}$$\infty$
$0$$0$$0$$0$$0$$\frac{ 1}{ 2}$
$1$$1$$1$$0$$1$$\frac{ 5}{ 6}$
$3$$1$$1$$0$$1$$\frac{ 7}{ 6}$
$4$$2$$2$$0$$2$$\frac{ 3}{ 2}$

#### Note:

This is operator "5.34" from ...