Summary

You searched for: sol=438912

Your search produced exactly one match

1

New Number: 8.72 |  AESZ:  |  Superseeker: 32/3 14279/9  |  Hash: d1b06e21c273cae807016268cd540d98  

Degree: 8

\(3^{2} \theta^4-2 3 x\theta(85\theta^3+176\theta^2+112\theta+24)-2^{2} x^{2}\left(6581\theta^4+25808\theta^3+38672\theta^2+26184\theta+6912\right)-x^{3}\left(433513\theta^4+2497158\theta^3+5333997\theta^2+4967532\theta+1724868\right)-2 x^{4}\left(1751393\theta^4+13178758\theta^3+35803021\theta^2+40983788\theta+16698948\right)-2^{2} x^{5}(\theta+1)(3719315\theta^3+30248511\theta^2+79801768\theta+66666732)-2^{3} 3^{3} x^{6}(\theta+1)(\theta+2)(144041\theta^2+1060683\theta+1963346)-2^{7} 3^{4} x^{7}(\theta+3)(\theta+2)(\theta+1)(2449\theta+10862)-2^{9} 3^{3} 7 71 x^{8}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 0, 192, 7524, 438912, ...
--> OEIS
Normalized instanton numbers (n0=1): 32/3, 284/3, 14279/9, 118940/3, 1226784, ... ; Common denominator:...

Discriminant

\(-(7z+1)(6z+1)(639z^2+87z-1)(2z+3)^2(8z+1)^2\)

Local exponents

\(-\frac{ 3}{ 2}\)\(-\frac{ 1}{ 6}\)\(-\frac{ 29}{ 426}-\frac{ 5}{ 142}\sqrt{ 5}\)\(-\frac{ 1}{ 7}\)\(-\frac{ 1}{ 8}\)\(0\)\(-\frac{ 29}{ 426}+\frac{ 5}{ 142}\sqrt{ 5}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(0\)\(0\)\(1\)\(2\)
\(3\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(3\)
\(4\)\(2\)\(2\)\(2\)\(1\)\(0\)\(2\)\(4\)

Note:

This is operator "8.72" from ...

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