Summary

You searched for: superseeker=66/7,8716/7

Your search produced exactly one match

1

New Number: 8.43 |  AESZ:  |  Superseeker: 66/7 8716/7  |  Hash: 923554dba37f79c41bf0f67b875c36f7  

Degree: 8

\(7^{2} \theta^4-2 7 x\left(452\theta^4+640\theta^3+509\theta^2+189\theta+28\right)+2^{2} x^{2}\left(47156\theta^4+78224\theta^3+63963\theta^2+31010\theta+7000\right)-2^{5} x^{3}\left(77224\theta^4+150936\theta^3+155876\theta^2+86751\theta+19838\right)+2^{8} x^{4}\left(65988\theta^4+160584\theta^3+193653\theta^2+117501\theta+28198\right)-2^{12} x^{5}\left(15712\theta^4+46888\theta^3+63382\theta^2+41163\theta+10338\right)+2^{16} x^{6}\left(2088\theta^4+7272\theta^3+10589\theta^2+7140\theta+1828\right)-2^{22} x^{7}\left(36\theta^4+138\theta^3+206\theta^2+137\theta+34\right)+2^{26} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 8, 224, 10016, 547936, ...
--> OEIS
Normalized instanton numbers (n0=1): 66/7, 573/7, 8716/7, 197852/7, 5617614/7, ... ; Common denominator:...

Discriminant

\((1-96z+256z^2)(4z-1)^2(128z^2-88z+7)^2\)

Local exponents

\(0\)\(\frac{ 3}{ 16}-\frac{ 1}{ 8}\sqrt{ 2}\)\(\frac{ 11}{ 32}-\frac{ 1}{ 32}\sqrt{ 65}\)\(\frac{ 1}{ 4}\)\(\frac{ 3}{ 16}+\frac{ 1}{ 8}\sqrt{ 2}\)\(\frac{ 11}{ 32}+\frac{ 1}{ 32}\sqrt{ 65}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(3\)\(1\)
\(0\)\(2\)\(4\)\(1\)\(2\)\(4\)\(1\)

Note:

This is operator "8.43" from ...

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