Summary

You searched for: superseeker=56/3,17704/3

Your search produced exactly one match

1

New Number: 8.49 |  AESZ:  |  Superseeker: 56/3 17704/3  |  Hash: 4fa01cbee2fc74e3a62e00386e6fa1c0  

Degree: 8

\(3^{2} \theta^4-2^{2} 3 x\left(29\theta^4+178\theta^3+134\theta^2+45\theta+6\right)-2^{5} x^{2}\left(2233\theta^4+2536\theta^3+607\theta^2+132\theta+12\right)-2^{10} x^{3}\left(1274\theta^4+7425\theta^3+20002\theta^2+12717\theta+2670\right)+2^{13} x^{4}\left(2539\theta^4-36538\theta^3-52775\theta^2-31122\theta-6192\right)+2^{20} x^{5}\left(1617\theta^4+9771\theta^3+4484\theta^2-674\theta-556\right)+2^{25} x^{6}\left(1135\theta^4+4272\theta^3+3439\theta^2+858\theta+16\right)-2^{31} 3 x^{7}(2\theta+1)(110\theta^3+225\theta^2+184\theta+57)+2^{37} 3^{2} x^{8}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 8, 264, 16640, 1130920, ...
--> OEIS
Normalized instanton numbers (n0=1): 56/3, -83/6, 17704/3, -25024/3, 13408832/3, ... ; Common denominator:...

Discriminant

\((4z-1)(131072z^3+2048z^2+88z-1)(48z+1)^2(64z-3)^2\)

Local exponents

\(-\frac{ 1}{ 48}\) ≈\(-0.01214-0.027095I\) ≈\(-0.01214+0.027095I\)\(0\) ≈\(0.008655\)\(\frac{ 3}{ 64}\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(4\)\(2\)\(2\)\(0\)\(2\)\(4\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "8.49" from ...

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