Summary

You searched for: superseeker=492/5,872164/5

Your search produced exactly one match

1

New Number: 5.37 |  AESZ: 221  |  Superseeker: 492/5 872164/5  |  Hash: b7ce7a734c057660ce3d6341a7572078  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(404\theta^4+1096\theta^3+773\theta^2+225\theta+25\right)-2^{4} x^{2}\left(66896\theta^4+137408\theta^3+101096\theta^2+52800\theta+11625\right)-2^{8} 3 5 x^{3}(2\theta+1)(5672\theta^3+9500\theta^2+8422\theta+2689)-2^{15} 3^{2} x^{4}(2\theta+1)(1208\theta^3+2892\theta^2+2842\theta+969)-2^{20} 3^{3} x^{5}(2\theta+1)(6\theta+5)(6\theta+7)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 20, 2988, 618320, 156299500, ...
--> OEIS
Normalized instanton numbers (n0=1): 492/5, 10376/5, 872164/5, 91316176/5, 12181916784/5, ... ; Common denominator:...

Discriminant

\(-(-1+432z)(16z+1)^2(192z+5)^2\)

Local exponents

\(-\frac{ 1}{ 16}\)\(-\frac{ 5}{ 192}\)\(0\)\(\frac{ 1}{ 432}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(\frac{ 1}{ 4}\)\(1\)\(0\)\(1\)\(\frac{ 5}{ 6}\)
\(\frac{ 3}{ 4}\)\(3\)\(0\)\(1\)\(\frac{ 7}{ 6}\)
\(1\)\(4\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.37" from ...

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