Summary

You searched for: superseeker=364/5,1264916

Your search produced exactly one match

1

New Number: 4.58 |  AESZ: 282  |  Superseeker: 364/5 1264916  |  Hash: 582c9abe0a0b8176a2a06ec6c223bef4  

Degree: 4

\(5^{2} \theta^4-2^{2} 5 x\left(1348\theta^4+752\theta^3+521\theta^2+145\theta+15\right)+2^{4} 3^{4} x^{2}\left(5696\theta^4-1792\theta^3-7304\theta^2-3740\theta-585\right)-2^{10} 3^{8} x^{3}\left(20\theta^4-360\theta^3-289\theta^2-90\theta-10\right)-2^{12} 3^{13} x^{4}\left((2\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 12, 3564, 1081200, 418200300, ...
--> OEIS
Normalized instanton numbers (n0=1): 364/5, 43384/5, 1264916, 1297643028/5, 323354425968/5, ... ; Common denominator:...

Discriminant

\(-(62208z^2+560z-1)(-5+1296z)^2\)

Local exponents

\(-\frac{ 35}{ 7776}-\frac{ 13}{ 7776}\sqrt{ 13}\)\(0\)\(s_1\)\(s_2\)\(-\frac{ 35}{ 7776}+\frac{ 13}{ 7776}\sqrt{ 13}\)\(\frac{ 5}{ 1296}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(3\)\(\frac{ 1}{ 2}\)
\(2\)\(0\)\(2\)\(2\)\(2\)\(4\)\(\frac{ 1}{ 2}\)

Note:

Sporadic Operator. There is a second MUM-point hiding at infinity,corresponding to the Operator AESZ 283/4.59

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