Summary

You searched for: superseeker=247,3584909

Your search produced exactly one match

1

New Number: 8.60 |  AESZ:  |  Superseeker: 247 3584909  |  Hash: 540ab51629d98ae18b7d061824bd258b  

Degree: 8

\(\theta^4-x\left(1182\theta^4+2172\theta^3+1519\theta^2+433\theta+46\right)+x^{2}\left(70937\theta^4+62468\theta^3-34151\theta^2-26294\theta-4528\right)-2^{3} x^{3}\left(140935\theta^4-41718\theta^3-83276\theta^2-29367\theta-3376\right)+2^{4} 3 x^{4}\left(21007\theta^4-134418\theta^3-100578\theta^2-26137\theta-1974\right)+2^{6} x^{5}\left(29420\theta^4+79292\theta^3-91933\theta^2-88917\theta-22012\right)-2^{6} x^{6}\left(17519\theta^4-73056\theta^3-66923\theta^2-16512\theta+1436\right)-2^{9} 5 x^{7}\left(351\theta^4+510\theta^3+176\theta^2-79\theta-46\right)-2^{12} 5^{2} x^{8}\left((\theta+1)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 46, 15670, 8332840, 5425831846, ...
--> OEIS
Normalized instanton numbers (n0=1): 247, 38017/2, 3584909, 2039721503/2, 359173241174, ... ; Common denominator:...

Discriminant

\(-(z+1)(64z^3+600z^2+1119z-1)(1-32z+40z^2)^2\)

Local exponents

≈\(-6.805514\) ≈\(-2.570379\)\(-1\)\(0\) ≈\(0.000893\)\(\frac{ 2}{ 5}-\frac{ 3}{ 20}\sqrt{ 6}\)\(\frac{ 2}{ 5}+\frac{ 3}{ 20}\sqrt{ 6}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(3\)\(3\)\(1\)
\(2\)\(2\)\(2\)\(0\)\(2\)\(4\)\(4\)\(1\)

Note:

This is operator "8.60" from ...

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex