Summary

You searched for: superseeker=23,16723

Your search produced exactly one match

1

New Number: 6.10 |  AESZ:  |  Superseeker: 23 16723  |  Hash: 23025d094839fb9d8e76076bd9a0bfa7  

Degree: 6

\(\theta^4-x\left(254\theta^4+508\theta^3+391\theta^2+137\theta+18\right)+x^{2}\left(4657\theta^4+18628\theta^3+27265\theta^2+17274\theta+3672\right)-2^{2} 3 x^{3}\left(2920\theta^4+17520\theta^3+36833\theta^2+31659\theta+8235\right)+2^{3} 3^{4} x^{4}\left(204\theta^4+1632\theta^3+4449\theta^2+4740\theta+1400\right)-2^{4} 3^{5} x^{5}(16\theta^2+80\theta+35)(2\theta+5)^2+2^{4} 3^{6} x^{6}(2\theta+11)(2\theta+7)(2\theta+5)(2\theta+1)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 18, 1242, 138420, 18954810, ...
--> OEIS
Normalized instanton numbers (n0=1): 23, 462, 16723, 923487, 61874817, ... ; Common denominator:...

Discriminant

\((3z-1)(3888z^3-1944z^2+243z-1)(4z-1)^2\)

Local exponents

\(0\) ≈\(0.004259\) ≈\(0.215449\)\(\frac{ 1}{ 4}\) ≈\(0.280292\)\(\frac{ 1}{ 3}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(\frac{ 5}{ 2}\)
\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(\frac{ 7}{ 2}\)
\(0\)\(2\)\(2\)\(1\)\(2\)\(2\)\(\frac{ 11}{ 2}\)

Note:

This is operator "6.10" from ...

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex