Summary

You searched for: superseeker=1312,127846048

Your search produced exactly one match

1

New Number: 5.118 |  AESZ: 416  |  Superseeker: 1312 127846048  |  Hash: 3ae3241981d64d9c9cc38b29974fa202  

Degree: 5

\(\theta^4+2^{4} x\left(560\theta^4-32\theta^3+56\theta^2+72\theta+15\right)+2^{15} x^{2}\left(896\theta^4+272\theta^3+604\theta^2+196\theta+21\right)+2^{24} 3^{2} x^{3}\left(288\theta^4+352\theta^3+364\theta^2+164\theta+29\right)+2^{35} 3^{3} x^{4}(2\theta+1)(16\theta^3+32\theta^2+28\theta+9)+2^{46} 3^{3} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, -240, 118032, -72810240, 50454043920, ...
--> OEIS
Normalized instanton numbers (n0=1): 1312, -301376, 127846048, -70845744192, 45645879602784, ... ; Common denominator:...

Discriminant

\((1+768z)(1024z+1)^2(3072z+1)^2\)

Local exponents

\(-\frac{ 1}{ 768}\)\(-\frac{ 1}{ 1024}\)\(-\frac{ 1}{ 3072}\)\(0\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(\frac{ 1}{ 2}\)\(1\)\(0\)\(1\)
\(1\)\(\frac{ 1}{ 2}\)\(3\)\(0\)\(1\)
\(2\)\(1\)\(4\)\(0\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.118" from ...

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