Summary

You searched for: superseeker=-988/3,-14008436/3

Your search produced exactly one match

1

New Number: 7.4 |  AESZ:  |  Superseeker: -988/3 -14008436/3  |  Hash: 9bddfb88498c0a263be6ca541ae7e980  

Degree: 7

\(3^{2} \theta^4+2^{2} 3 x\left(760\theta^4+2048\theta^3+1423\theta^2+399\theta+42\right)-2^{7} x^{2}\left(20440\theta^4+25216\theta^3-4415\theta^2-4845\theta-795\right)+2^{12} x^{3}\left(39928\theta^4+16512\theta^3+23719\theta^2+11637\theta+1830\right)+2^{17} x^{4}\left(2928\theta^4-41856\theta^3-42871\theta^2-16873\theta-2425\right)+2^{23} x^{5}\left(608\theta^4+3968\theta^3+10676\theta^2+6177\theta+1089\right)+2^{29} x^{6}\left(272\theta^4+1056\theta^3+861\theta^2+264\theta+27\right)+2^{35} x^{7}\left((2\theta+1)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, -56, 21096, -12540800, 9146271400, ...
--> OEIS
Normalized instanton numbers (n0=1): -988/3, 57289/3, -14008436/3, 1385404666, -1599785191904/3, ... ; Common denominator:...

Discriminant

\((1+1248z-10240z^2+131072z^3)(-3+352z+2048z^2)^2\)

Local exponents

\(-\frac{ 11}{ 128}-\frac{ 1}{ 128}\sqrt{ 145}\) ≈\(-0.000796\)\(0\)\(-\frac{ 11}{ 128}+\frac{ 1}{ 128}\sqrt{ 145}\) ≈\(0.039461-0.089595I\) ≈\(0.039461+0.089595I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(3\)\(1\)\(0\)\(3\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(4\)\(2\)\(0\)\(4\)\(2\)\(2\)\(\frac{ 1}{ 2}\)

Note:

This is operator "7.4" from ...

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex