Summary

You searched for: superseeker=-84/11,-9052/11

Your search produced exactly one match

1

New Number: 5.25 |  AESZ: 198  |  Superseeker: -84/11 -9052/11  |  Hash: a1f924763b047c2720d99cfca5ca63db  

Degree: 5

\(11^{2} \theta^4+7 11 x\left(130\theta^4+266\theta^3+210\theta^2+77\theta+11\right)-x^{2}\left(11198+55253\theta+103725\theta^2+89990\theta^3+32126\theta^4\right)+x^{3}\left(1716+20625\theta+63474\theta^2+74184\theta^3+28723\theta^4\right)-7 x^{4}\left(1135\theta^4+2336\theta^3+1881\theta^2+713\theta+110\right)+7^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -7, 199, -8359, 423751, ...
--> OEIS
Normalized instanton numbers (n0=1): -84/11, 639/11, -9052/11, 189021/11, -4838013/11, ... ; Common denominator:...

Discriminant

\((z^3-159z^2+84z+1)(-11+7z)^2\)

Local exponents

≈\(-0.011648\)\(0\) ≈\(0.541757\)\(\frac{ 11}{ 7}\) ≈\(158.469891\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to Operator AESZ 193/5.22

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