Summary

You searched for: Spectrum0=1/3,1,1,5/3

Your search produced exactly one match

1

New Number: 5.8 |  AESZ:  |  Superseeker: 84 1522388/3  |  Hash: f4b2a154823e983e64682b48f6254a15  

Degree: 5

\(\theta^4-2^{2} 3 x\left(192\theta^4+240\theta^3+191\theta^2+71\theta+10\right)+2^{7} 3^{2} x^{2}\left(1746\theta^4+3960\theta^3+4323\theta^2+2247\theta+395\right)-2^{12} 3^{4} x^{3}\left(2538\theta^4+7776\theta^3+9915\theta^2+5643\theta+1030\right)+2^{17} 3^{6} x^{4}\left(1782\theta^4+6480\theta^3+8793\theta^2+4905\theta+875\right)-2^{23} 3^{11} x^{5}(\theta+1)^2(3\theta+1)(3\theta+5)\)

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Coefficients of the holomorphic solution: 1, 120, 34920, 13157760, 5790070440, ...
--> OEIS
Normalized instanton numbers (n0=1): 84, 9210, 1522388/3, 120348978, 19186016160, ... ; Common denominator:...

Discriminant

\(-(-1+864z)(432z-1)^2(288z-1)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 864}\)\(\frac{ 1}{ 432}\)\(\frac{ 1}{ 288}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 3}\)
\(0\)\(1\)\(\frac{ 1}{ 6}\)\(1\)\(1\)
\(0\)\(1\)\(\frac{ 5}{ 6}\)\(3\)\(1\)
\(0\)\(2\)\(1\)\(4\)\(\frac{ 5}{ 3}\)

Note:

This is operator "5.8" from ...

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