Summary

You searched for: superseeker=7/3,-4843/81

Your search produced exactly one match

1

New Number: 5.94 |  AESZ: 334  |  Superseeker: 7/3 -4843/81  |  Hash: 1ab1dce2847b14dd89a8f8f48ddc7214  

Degree: 5

\(3^{2} \theta^4-3 x\left(166\theta^4+320\theta^3+271\theta^2+111\theta+18\right)+x^{2}\left(11155\theta^4+42652\theta^3+60463\theta^2+36876\theta+8172\right)-3^{2} x^{3}\left(4705\theta^4+23418\theta^3+42217\theta^2+31152\theta+7932\right)+2^{2} 3 x^{4}\left(3514\theta^4+16403\theta^3+25581\theta^2+16442\theta+3744\right)-2^{2} 5 x^{5}(5\theta+3)(5\theta+4)(5\theta+6)(5\theta+7)\)

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Coefficients of the holomorphic solution: 1, 6, 54, 240, -9450, ...
--> OEIS
Normalized instanton numbers (n0=1): 7/3, -79/12, -4843/81, -1058/3, 3620/3, ... ; Common denominator:...

Discriminant

\(-(3125z^3-1167z^2+54z-1)(2z-3)^2\)

Local exponents

\(0\) ≈\(0.025215-0.018839I\) ≈\(0.025215+0.018839I\) ≈\(0.32301\)\(\frac{ 3}{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 3}{ 5}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 4}{ 5}\)
\(0\)\(1\)\(1\)\(1\)\(3\)\(\frac{ 6}{ 5}\)
\(0\)\(2\)\(2\)\(2\)\(4\)\(\frac{ 7}{ 5}\)

Note:

This is operator "5.94" from ...

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