Summary

You searched for: superseeker=5/7,48/7

Your search produced exactly one match

1

New Number: 5.81 |  AESZ: 312  |  Superseeker: 5/7 48/7  |  Hash: 767262575f8b1458839c1e9a8beacf0a  

Degree: 5

\(7^{2} \theta^4-7 x\left(39\theta^4+234\theta^3+201\theta^2+84\theta+14\right)-2 x^{2}\left(12073\theta^4+43222\theta^3+57461\theta^2+34328\theta+7756\right)-2^{2} x^{3}\left(28923\theta^4+48426\theta^3-33393\theta^2-80976\theta-32032\right)+2^{3} 13 x^{4}\left(359\theta^4+9790\theta^3+20805\theta^2+15784\theta+4124\right)+2^{5} 3 13^{2} x^{5}(\theta+1)^2(6\theta+5)(6\theta+7)\)

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Coefficients of the holomorphic solution: 1, 2, 30, 308, 5950, ...
--> OEIS
Normalized instanton numbers (n0=1): 5/7, 239/28, 48/7, 4451/14, 5888/7, ... ; Common denominator:...

Discriminant

\((16z+1)(2z-1)(27z-1)(7+26z)^2\)

Local exponents

\(-\frac{ 7}{ 26}\)\(-\frac{ 1}{ 16}\)\(0\)\(\frac{ 1}{ 27}\)\(\frac{ 1}{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 5}{ 6}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(4\)\(2\)\(0\)\(2\)\(2\)\(\frac{ 7}{ 6}\)

Note:

This is operator "5.81" from ...

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