Summary

You searched for: superseeker=32,8608

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1

New Number: 8.70 |  AESZ:  |  Superseeker: 32 8608  |  Hash: 664bcad4360eb63fde0fdd3018aed2f2  

Degree: 8

\(\theta^4-2^{4} x\left(19\theta^4+26\theta^3+20\theta^2+7\theta+1\right)+2^{9} x^{2}\left(61\theta^4+94\theta^3+89\theta^2+47\theta+10\right)-2^{14} x^{3}\left(134\theta^4+156\theta^3+37\theta^2+18\theta+6\right)+2^{19} x^{4}\left(192\theta^4+216\theta^3+58\theta^2-32\theta-17\right)-2^{24} x^{5}\left(191\theta^4+158\theta^3+183\theta^2+68\theta+6\right)+2^{29} x^{6}\left(125\theta^4+138\theta^3+135\theta^2+72\theta+16\right)-2^{35} x^{7}\left(20\theta^4+46\theta^3+47\theta^2+24\theta+5\right)+2^{41} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 16, 848, 72448, 7745296, ...
--> OEIS
Normalized instanton numbers (n0=1): 32, 504, 8608, 475061, 28268384, ... ; Common denominator:...

Discriminant

\((16z-1)(32z-1)(1024z^2-192z+1)(1-32z+2048z^2)^2\)

Local exponents

\(0\)\(\frac{ 3}{ 32}-\frac{ 1}{ 16}\sqrt{ 2}\)\(\frac{ 1}{ 128}-\frac{ 1}{ 128}\sqrt{ 7}I\)\(\frac{ 1}{ 128}+\frac{ 1}{ 128}\sqrt{ 7}I\)\(\frac{ 1}{ 32}\)\(\frac{ 1}{ 16}\)\(\frac{ 3}{ 32}+\frac{ 1}{ 16}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(3\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(4\)\(4\)\(2\)\(2\)\(2\)\(1\)

Note:

This is operator "8.70" from ...

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