Summary

You searched for: superseeker=286,12179050/3

Your search produced exactly one match

1

New Number: 8.58 |  AESZ:  |  Superseeker: 286 12179050/3  |  Hash: 870f2e78b48eb5ee8f5de2f6a438f2b8  

Degree: 8

\(\theta^4-x\left(1114\theta^4+2444\theta^3+1704\theta^2+482\theta+51\right)-x^{2}\left(85922\theta^4+94748\theta^3-21782\theta^2-21164\theta-3273\right)-3^{2} x^{3}\left(173242\theta^4+41004\theta^3+55912\theta^2+32322\theta+5679\right)+3^{2} x^{4}\left(189512\theta^4-918380\theta^3-841954\theta^2-306732\theta-47331\right)+3^{4} x^{5}\left(30338\theta^4+90716\theta^3-87560\theta^2-90566\theta-23193\right)-3^{4} x^{6}\left(19406\theta^4-68364\theta^3-62162\theta^2-14148\theta+1989\right)-3^{6} 5 x^{7}\left(278\theta^4+340\theta^3+8\theta^2-162\theta-63\right)-3^{8} 5^{2} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 51, 18267, 10280301, 7092708939, ...
--> OEIS
Normalized instanton numbers (n0=1): 286, 38919/2, 12179050/3, 2393489451/2, 439227114444, ... ; Common denominator:...

Discriminant

\(-(z+1)(81z^3+549z^2+1187z-1)(-1-36z+45z^2)^2\)

Local exponents

≈\(-3.38931-1.781181I\) ≈\(-3.38931+1.781181I\)\(-1\)\(\frac{ 2}{ 5}-\frac{ 1}{ 15}\sqrt{ 41}\)\(0\) ≈\(0.000842\)\(\frac{ 2}{ 5}+\frac{ 1}{ 15}\sqrt{ 41}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(1\)\(3\)\(0\)\(1\)\(3\)\(1\)
\(2\)\(2\)\(2\)\(4\)\(0\)\(2\)\(4\)\(1\)

Note:

This is operator "8.58" from ...

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