Summary

You searched for: superseeker=2043/5,88982631/5

Your search produced exactly one match

1

New Number: 4.68 |  AESZ: 337  |  Superseeker: 2043/5 88982631/5  |  Hash: dc26e94a7c1daba6f627be36c42019b7  

Degree: 4

\(5^{2} \theta^4-3 5 x\left(3483\theta^4+6102\theta^3+4241\theta^2+1190\theta+120\right)+2^{5} 3^{2} x^{2}\left(31428\theta^4+35559\theta^3+243\theta^2-4320\theta-740\right)-2^{8} 3^{5} x^{3}\left(7371\theta^4+4860\theta^3+2997\theta^2+1080\theta+140\right)+2^{13} 3^{8} x^{4}(3\theta+1)^2(3\theta+2)^2\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 72, 41400, 37396800, 41397463800, ...
--> OEIS
Normalized instanton numbers (n0=1): 2043/5, 279018/5, 88982631/5, 8604708876, 25774859896713/5, ... ; Common denominator:...

Discriminant

\((23328z^2-1917z+1)(-5+432z)^2\)

Local exponents

\(0\)\(s_1\)\(s_2\)\(\frac{ 71}{ 1728}-\frac{ 17}{ 1728}\sqrt{ 17}\)\(\frac{ 5}{ 432}\)\(\frac{ 71}{ 1728}+\frac{ 17}{ 1728}\sqrt{ 17}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 3}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 3}\)
\(0\)\(1\)\(1\)\(1\)\(3\)\(1\)\(\frac{ 2}{ 3}\)
\(0\)\(2\)\(2\)\(2\)\(4\)\(2\)\(\frac{ 2}{ 3}\)

Note:

Sporadic Operator.

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex