Summary

You searched for: superseeker=-24/5,-1608/5

Your search produced exactly one match

1

New Number: 8.65 |  AESZ:  |  Superseeker: -24/5 -1608/5  |  Hash: 5e457fa5807a784e24220c973aeceba8

Degree: 8

$5^{2} \theta^4+2^{2} 5 x\left(73\theta^4+122\theta^3+96\theta^2+35\theta+5\right)-2^{4} x^{2}\left(134\theta^4+2072\theta^3+3924\theta^2+2660\theta+645\right)-2^{6} x^{3}\left(708\theta^4+672\theta^3-2898\theta^2-3750\theta-1285\right)+2^{10} x^{4}\left(110\theta^4+700\theta^3+498\theta^2-56\theta-105\right)+2^{12} x^{5}\left(61\theta^4-266\theta^3-544\theta^2-373\theta-88\right)-2^{14} x^{6}\left(86\theta^4+168\theta^3+172\theta^2+108\theta+31\right)+2^{16} x^{7}\left(32\theta^4+112\theta^3+158\theta^2+102\theta+25\right)-2^{20} x^{8}\left((\theta+1)^4\right)$

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Coefficients of the holomorphic solution: 1, -4, 92, -2704, 95596, ...
--> OEIS
Normalized instanton numbers (n0=1): -24/5, 329/10, -1608/5, 48409/10, -455264/5, ... ; Common denominator:...

Discriminant

$-(4z-1)(256z^3-192z^2+56z+1)(-5-16z+32z^2)^2$

Local exponents

$\frac{ 1}{ 4}-\frac{ 1}{ 8}\sqrt{ 14}$ ≈$-0.016861$$0$$\frac{ 1}{ 4}$ ≈$0.38343-0.290965I$ ≈$0.38343+0.290965I$$\frac{ 1}{ 4}+\frac{ 1}{ 8}\sqrt{ 14}$$\infty$
$0$$0$$0$$0$$0$$0$$0$$1$
$1$$1$$0$$1$$1$$1$$1$$1$
$3$$1$$0$$1$$1$$1$$3$$1$
$4$$2$$0$$2$$2$$2$$4$$1$

Note:

This is operator "8.65" from ...