Summary

You searched for: superseeker=-18/5,-642/5

Your search produced exactly one match

1

New Number: 5.58 |  AESZ: 266  |  Superseeker: -18/5 -642/5  |  Hash: 5d46913a13c5fa5fa6a547d8b5646133  

Degree: 5

\(5^{2} \theta^4-3 5 x\left(27\theta^4+108\theta^3+124\theta^2+70\theta+15\right)-2 3^{2} x^{2}\left(1377\theta^4+4536\theta^3+6507\theta^2+4455\theta+1220\right)+2 3^{5} x^{3}\left(567\theta^4+4860\theta^3+11583\theta^2+10665\theta+3445\right)+3^{8} x^{4}\left(729\theta^4+3888\theta^3+6606\theta^2+4662\theta+1184\right)+3^{15} x^{5}\left((\theta+1)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 9, 171, 3087, 69579, ...
--> OEIS
Normalized instanton numbers (n0=1): -18/5, 117/10, -642/5, 1197, -76788/5, ... ; Common denominator:...

Discriminant

\((1+27z)(27z+5)^2(27z-1)^2\)

Local exponents

\(-\frac{ 5}{ 27}\)\(-\frac{ 1}{ 27}\)\(0\)\(\frac{ 1}{ 27}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(0\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)
\(4\)\(2\)\(0\)\(1\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to
Operator AESZ 267/5.59

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex