Summary

You searched for: superseeker=-140/3,-66092

Your search produced exactly one match

1

New Number: 5.95 |  AESZ: 338  |  Superseeker: -140/3 -66092  |  Hash: eb4f6d6e59fafa4e794fb664dbdeab3f  

Degree: 5

\(3^{2} \theta^4+2^{2} 3 x\left(278\theta^4+424\theta^3+311\theta^2+99\theta+12\right)+2^{5} x^{2}\left(5210\theta^4+3944\theta^3-2635\theta^2-2433\theta-492\right)+2^{8} x^{3}\left(8190\theta^4-3528\theta^3-3991\theta^2-585\theta+114\right)-2^{11} 11 x^{4}(2\theta+1)(86\theta^3+57\theta^2-39\theta-32)+2^{15} 11^{2} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, -16, 1608, -243520, 44810920, ...
--> OEIS
Normalized instanton numbers (n0=1): -140/3, 1293, -66092, 5236719, -1553321056/3, ... ; Common denominator:...

Discriminant

\((2048z^3-640z^2+312z+1)(3+88z)^2\)

Local exponents

\(-\frac{ 3}{ 88}\) ≈\(-0.003184\)\(0\) ≈\(0.157842-0.358378I\) ≈\(0.157842+0.358378I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(4\)\(2\)\(0\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.95" from ...

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