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You searched for: Spectrum0=1,2,3,4

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New Number: 8.82 |  AESZ:  |  Superseeker: 0 -1/3  |  Hash: 8bab1ddc8b31cb2c21f01402f27895ce  

Degree: 8

\(\theta^4-x\theta(3\theta^3-6\theta^2-4\theta-1)-x^{2}\left(211\theta^4+856\theta^3+1433\theta^2+1184\theta+384\right)+2 x^{3}\left(761\theta^4+3288\theta^3+6477\theta^2+6654\theta+2700\right)+2^{2} x^{4}(\theta+1)(2013\theta^3+17379\theta^2+40726\theta+28548)-2^{3} x^{5}(\theta+1)(15719\theta^3+126105\theta^2+325408\theta+269508)+2^{5} 3^{2} x^{6}(\theta+1)(\theta+2)(1817\theta^2+11967\theta+19631)-2^{7} 3^{4} x^{7}(\theta+3)(\theta+2)(\theta+1)(89\theta+350)+2^{9} 3^{3} 43 x^{8}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 0, 24, -72, 1296, ...
--> OEIS
Normalized instanton numbers (n0=1): 0, 1/2, -1/3, -1, -2, ... ; Common denominator:...

Discriminant

\((6z-1)(4z-1)(43z^2-13z+1)(12z+1)^2(-1+2z)^2\)

Local exponents

\(-\frac{ 1}{ 12}\)\(0\)\(\frac{ 13}{ 86}-\frac{ 1}{ 86}\sqrt{ 3}I\)\(\frac{ 13}{ 86}+\frac{ 1}{ 86}\sqrt{ 3}I\)\(\frac{ 1}{ 6}\)\(\frac{ 1}{ 4}\)\(\frac{ 1}{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(2\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)\(1\)\(1\)\(3\)\(3\)
\(1\)\(0\)\(2\)\(2\)\(2\)\(2\)\(4\)\(4\)

Note:

This is operator "8.82" from ...

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