Summary

You searched for: sol=966020/81

Your search produced exactly one match

1

New Number: 6.34 |  AESZ:  |  Superseeker: 4/3 -124/81  |  Hash: 1153f8807d42d96ede28f7a8d06c144b  

Degree: 6

\(3^{2} \theta^4-2^{2} 3 x\left(8\theta^4+16\theta^3+27\theta^2+19\theta+5\right)-2^{4} x^{2}\left(272\theta^4+1088\theta^3+1984\theta^2+1792\theta+621\right)+2^{8} x^{3}\left(192\theta^4+1152\theta^3+3448\theta^2+5160\theta+3101\right)+2^{12} x^{4}\left(112\theta^4+896\theta^3+2432\theta^2+2560\theta+753\right)-2^{16} x^{5}\left(96\theta^4+960\theta^3+3860\theta^2+7300\theta+5389\right)+2^{24} x^{6}\left((\theta+3)^4\right)\)

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Coefficients of the holomorphic solution: 1, 20/3, 332/3, 13360/27, 966020/81, ...
--> OEIS
Normalized instanton numbers (n0=1): 4/3, -14/9, -124/81, -4498/243, 37024/729, ... ; Common denominator:...

Discriminant

\((16z-1)^2(16z-3)^2(16z+1)^2\)

Local exponents

\(-\frac{ 1}{ 16}\)\(0\)\(\frac{ 1}{ 16}\)\(\frac{ 3}{ 16}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(3\)
\(0\)\(0\)\(\frac{ 1}{ 2}\)\(1\)\(3\)
\(1\)\(0\)\(\frac{ 1}{ 2}\)\(-2\)\(3\)
\(1\)\(0\)\(1\)\(3\)\(3\)

Note:

This is operator "6.34" from ...

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