Summary

You searched for: sol=90720

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1

New Number: 5.43 |  AESZ: 234  |  Superseeker: 18/7 5676/7  |  Hash: 3e70b30959c0c3bd799b435b9c842186  

Degree: 5

\(7^{2} \theta^4-2 7 x\theta(192\theta^3+60\theta^2+37\theta+7)-2^{2} x^{2}\left(17608\theta^4+115144\theta^3+166715\theta^2+94556\theta+18816\right)+2^{4} 3^{2} x^{3}\left(20288\theta^4+57288\theta^3+27524\theta^2-7455\theta-5026\right)-2^{6} 3^{5} x^{4}(2\theta+1)(458\theta^3-657\theta^2-1799\theta-846)-2^{12} 3^{8} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 0, 96, 1440, 90720, ...
--> OEIS
Normalized instanton numbers (n0=1): 18/7, 515/7, 5676/7, 133796/7, 2929726/7, ... ; Common denominator:...

Discriminant

\(-(64z-1)(36z+1)(4z+1)(-7+108z)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(-\frac{ 1}{ 36}\)\(0\)\(\frac{ 1}{ 64}\)\(\frac{ 7}{ 108}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(3\)\(1\)
\(2\)\(2\)\(0\)\(2\)\(4\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.43" from ...

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