Summary

You searched for: sol=832950

Your search produced exactly one match

1

New Number: 5.111 |  AESZ: 380  |  Superseeker: 12 2320  |  Hash: 85214e3836a67470a05358a4d38fb124  

Degree: 5

\(\theta^4-2 x\left(60\theta^4+90\theta^3+68\theta^2+23\theta+3\right)+2^{2} x^{2}\left(313\theta^4-398\theta^3-1417\theta^2-1033\theta-252\right)+2^{3} x^{3}\left(654\theta^4+5064\theta^3+3574\theta^2+129\theta-405\right)-2^{4} 5 x^{4}\left(628\theta^4-40\theta^3-1699\theta^2-1661\theta-480\right)-2^{6} 3 5^{2} x^{5}(\theta+1)^2(6\theta+5)(6\theta+7)\)

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Coefficients of the holomorphic solution: 1, 6, 246, 13020, 832950, ...
--> OEIS
Normalized instanton numbers (n0=1): 12, 511/4, 2320, 63507, 2180312, ... ; Common denominator:...

Discriminant

\(-(108z-1)(4z+1)^2(10z-1)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(0\)\(\frac{ 1}{ 108}\)\(\frac{ 1}{ 10}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 5}{ 6}\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)\(1\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(3\)\(1\)
\(1\)\(0\)\(2\)\(4\)\(\frac{ 7}{ 6}\)

Note:

This is operator "5.111" from ...

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