Summary

You searched for: sol=688

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1

New Number: 5.4 |  AESZ: 21  |  Superseeker: 8/5 152/5  |  Hash: 42a2bc0f0ee2a405ede956176c95721f  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(36\theta^4+84\theta^3+72\theta^2+30\theta+5\right)-2^{4} x^{2}\left(181\theta^4+268\theta^3+71\theta^2-70\theta-35\right)+2^{8} x^{3}(\theta+1)(37\theta^3+248\theta^2+375\theta+165)+2^{10} x^{4}\left(39\theta^4+198\theta^3+331\theta^2+232\theta+59\right)+2^{15} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 4, 44, 688, 13036, ...
--> OEIS
Normalized instanton numbers (n0=1): 8/5, 57/10, 152/5, 253, 11552/5, ... ; Common denominator:...

Discriminant

\((4z+1)(32z-1)(4z-1)(8z+5)^2\)

Local exponents

\(-\frac{ 5}{ 8}\)\(-\frac{ 1}{ 4}\)\(0\)\(\frac{ 1}{ 32}\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(4\)\(2\)\(0\)\(2\)\(2\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to
Operator AESZ 71/5.11

A-Incarnation: (2,0),(02),(1,1),(1,1),(1,1) intersection in $P^4 \times P^4$

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2

New Number: 12.4 |  AESZ:  |  Superseeker: 4 -228/5  |  Hash: c24070a1d4a449404cd7b46398fa6d6e  

Degree: 12

\(5^{2} \theta^4-2^{2} 5^{2} x\left(16\theta^4+32\theta^3+31\theta^2+15\theta+3\right)+2^{4} 5 x^{2}\left(736\theta^4+2368\theta^3+3848\theta^2+2960\theta+915\right)-2^{10} 5 x^{3}\left(304\theta^4+1176\theta^3+2337\theta^2+2313\theta+891\right)+2^{12} 3 x^{4}\left(2608\theta^4+10688\theta^3+21652\theta^2+23580\theta+9945\right)-2^{16} 3 x^{5}\left(2784\theta^4+11616\theta^3+21812\theta^2+22396\theta+9191\right)+2^{21} 3 x^{6}\left(1232\theta^4+5232\theta^3+9332\theta^2+7968\theta+2649\right)-2^{25} 3^{2} x^{7}\left(304\theta^4+1312\theta^3+2472\theta^2+1992\theta+559\right)+2^{30} 3 x^{8}\left(280\theta^4+1216\theta^3+2491\theta^2+2337\theta+827\right)-2^{32} x^{9}\left(1664\theta^4+7200\theta^3+13692\theta^2+11988\theta+3951\right)+2^{38} x^{10}\left(164\theta^4+832\theta^3+1751\theta^2+1731\theta+663\right)-2^{40} x^{11}\left(160\theta^4+928\theta^3+2072\theta^2+2072\theta+777\right)+2^{44} x^{12}\left((2\theta+3)^4\right)\)

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Coefficients of the holomorphic solution: 1, 12, 108, 688, 3564, ...
--> OEIS
Normalized instanton numbers (n0=1): 4, -29/5, -228/5, 3724/5, -31856/5, ... ; Common denominator:...

Discriminant

\((16z-1)^2(256z^2-16z+1)^2(4096z^3-768z^2-5)^2\)

Local exponents

≈\(-0.013312-0.074322I\) ≈\(-0.013312+0.074322I\)\(0\)\(\frac{ 1}{ 32}-\frac{ 1}{ 32}\sqrt{ 3}I\)\(\frac{ 1}{ 32}+\frac{ 1}{ 32}\sqrt{ 3}I\)\(\frac{ 1}{ 16}\) ≈\(0.214124\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 3}{ 2}\)
\(1\)\(1\)\(0\)\(\frac{ 1}{ 2}\)\(\frac{ 1}{ 2}\)\(\frac{ 1}{ 2}\)\(1\)\(\frac{ 3}{ 2}\)
\(3\)\(3\)\(0\)\(\frac{ 1}{ 2}\)\(\frac{ 1}{ 2}\)\(\frac{ 1}{ 2}\)\(3\)\(\frac{ 3}{ 2}\)
\(4\)\(4\)\(0\)\(1\)\(1\)\(1\)\(4\)\(\frac{ 3}{ 2}\)

Note:

This is operator "12.4" from ...

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