Summary

You searched for: sol=636

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1

New Number: 7.7 |  AESZ:  |  Superseeker: 2/3 13/3  |  Hash: c7abb9c42d46f14955f0f23351082bef  

Degree: 7

\(3^{2} \theta^4-2 3 x\left(88\theta^4+110\theta^3+103\theta^2+48\theta+9\right)+2^{2} x^{2}\left(2923\theta^4+6610\theta^3+8041\theta^2+4908\theta+1206\right)-x^{3}\left(123365\theta^4+374814\theta^3+519741\theta^2+346176\theta+89676\right)+2 x^{4}\left(309657\theta^4+1102938\theta^3+1591157\theta^2+1032920\theta+249740\right)-2^{3} 11 x^{5}(\theta+1)(12897\theta^3+35469\theta^2+31181\theta+8042)-2^{3} 11^{2} x^{6}(\theta+1)(\theta+2)(355\theta^2+1047\theta+806)-2^{4} 11^{3} x^{7}(\theta+1)(\theta+2)^2(\theta+3)\)

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Coefficients of the holomorphic solution: 1, 6, 56, 636, 8196, ...
--> OEIS
Normalized instanton numbers (n0=1): 2/3, 5/3, 13/3, 59/3, 119, ... ; Common denominator:...

Discriminant

\(-(11z-1)(4z^2+22z-1)(z^2+11z-1)(-3+22z)^2\)

Local exponents

\(-\frac{ 11}{ 2}-\frac{ 5}{ 2}\sqrt{ 5}\)\(-\frac{ 11}{ 4}-\frac{ 5}{ 4}\sqrt{ 5}\)\(0\)\(-\frac{ 11}{ 4}+\frac{ 5}{ 4}\sqrt{ 5}\)\(-\frac{ 11}{ 2}+\frac{ 5}{ 2}\sqrt{ 5}\)\(\frac{ 1}{ 11}\)\(\frac{ 3}{ 22}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(2\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(3\)\(2\)
\(2\)\(2\)\(0\)\(2\)\(2\)\(2\)\(4\)\(3\)

Note:

This is operator "7.7" from ...

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