Summary

You searched for: sol=5433616

Your search produced exactly one match

1

New Number: 5.63 |  AESZ: 271  |  Superseeker: 10912 71557619232  |  Hash: c20fda7ad02ecc06f9b3f74bf4327d05  

Degree: 5

\(\theta^4+2^{4} x\left(2304\theta^4-3072\theta^3-2224\theta^2-688\theta-121\right)+2^{17} x^{2}\left(1792\theta^4-8192\theta^3+920\theta^2+344\theta+235\right)-2^{28} x^{3}\left(8704\theta^4+6144\theta^3+9872\theta^2+4368\theta+1201\right)-2^{44} 5 x^{4}\left(48\theta^4-37\theta^2-37\theta-13\right)+2^{60} 5^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 1936, 5433616, 17299986688, 58672579116304, ...
--> OEIS
Normalized instanton numbers (n0=1): 10912, -20731504, 71557619232, -326717237089712, 1743820693922321120, ... ; Common denominator:...

Discriminant

\((1+4096z)(20480z+1)^2(4096z-1)^2\)

Local exponents

\(-\frac{ 1}{ 4096}\)\(-\frac{ 1}{ 20480}\)\(0\)\(\frac{ 1}{ 4096}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(-\frac{ 1}{ 4}\)\(1\)
\(1\)\(3\)\(0\)\(1\)\(1\)
\(2\)\(4\)\(0\)\(\frac{ 5}{ 4}\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to Operator AESZ 270 /5.62

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