Summary

You searched for: sol=5280

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1

New Number: 8.86 |  AESZ:  |  Superseeker: 226/35 3959/7  |  Hash: 815127e123ce989d9ab793a009bb2e6a  

Degree: 8

\(5^{2} 7^{2} \theta^4-5 7 x\left(3223\theta^4+4862\theta^3+3866\theta^2+1435\theta+210\right)-x^{2}\left(6440-193270\theta-1217171\theta^2-2477628\theta^3-1818051\theta^4\right)-2^{4} 3 x^{3}\left(248985\theta^4+335357\theta^3+239138\theta^2+105280\theta+22400\right)+2^{6} x^{4}\left(618707\theta^4+1107118\theta^3+1179459\theta^2+710680\theta+177284\right)-2^{11} 3 x^{5}\left(12903\theta^4+34738\theta^3+48739\theta^2+33712\theta+8972\right)+2^{15} x^{6}\left(3323\theta^4+12570\theta^3+20137\theta^2+14550\theta+3916\right)-2^{20} x^{7}(\theta+1)(99+295\theta+286\theta^2+88\theta^3)+2^{25} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 6, 146, 5280, 229986, ...
--> OEIS
Normalized instanton numbers (n0=1): 226/35, 1599/35, 3959/7, 51101/5, 8052703/35, ... ; Common denominator:...

Discriminant

\((1-77z+251z^2-352z^3+512z^4)(32z-5)^2(8z-7)^2\)

Local exponents

\(0\)\(\frac{ 5}{ 32}\)\(\frac{ 7}{ 8}\)\(#ND+#NDI\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(3\)\(3\)\(1\)\(1\)
\(0\)\(4\)\(4\)\(2\)\(1\)

Note:

This is operator "8.86" from ...

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