Summary

You searched for: sol=4634280

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1

New Number: 5.17 |  AESZ: 119  |  Superseeker: 28/3 3892/3  |  Hash: dc8ec37012f2c92c83e6519935956eeb  

Degree: 5

\(3^{2} \theta^4-2^{2} 3 x\left(256\theta^4+320\theta^3+271\theta^2+111\theta+18\right)+2^{7} x^{2}\left(3104\theta^4+7040\theta^3+8012\theta^2+4452\theta+927\right)-2^{15} x^{3}\left(752\theta^4+2304\theta^3+3042\theta^2+1854\theta+405\right)+2^{21} x^{4}(2\theta+1)(176\theta^3+552\theta^2+622\theta+231)-2^{31} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 24, 1128, 67200, 4634280, ...
--> OEIS
Normalized instanton numbers (n0=1): 28/3, 394/3, 3892/3, 108262/3, 1044128, ... ; Common denominator:...

Discriminant

\(-(-1+128z)(64z-1)^2(128z-3)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 128}\)\(\frac{ 1}{ 64}\)\(\frac{ 3}{ 128}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(\frac{ 1}{ 4}\)\(1\)\(1\)
\(0\)\(1\)\(\frac{ 3}{ 4}\)\(3\)\(1\)
\(0\)\(2\)\(1\)\(4\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.17" from ...

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