Summary

You searched for: sol=44

Your search produced 5 matches

You can download all data as plain text or as JSON

1

New Number: 3.27 |  AESZ: 408  |  Superseeker: -60 -61780  |  Hash: 32ab77c73baf49023973ad11e5d0852e  

Degree: 3

\(\theta^4-2^{2} x(2\theta+1)(46\theta^3+53\theta^2+45\theta+11)-2^{4} x^{2}(8\theta+7)(64\theta^3+312\theta^2+440\theta+135)+2^{8} 3^{2} x^{3}(8\theta+3)(8\theta+7)(8\theta+15)(8\theta+19)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 44, 6060, 972720, 182017260, ...
--> OEIS
Normalized instanton numbers (n0=1): -60, 975, -61780, 4166460, -1853578608/5, ... ; Common denominator:...

Discriminant

\((144z+1)(-1+256z)^2\)

Local exponents

\(-\frac{ 1}{ 144}\)\(0\)\(\frac{ 1}{ 256}\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 3}{ 8}\)
\(1\)\(0\)\(\frac{ 1}{ 4}\)\(\frac{ 7}{ 8}\)
\(1\)\(0\)\(1\)\(\frac{ 15}{ 8}\)
\(2\)\(0\)\(\frac{ 5}{ 4}\)\(\frac{ 19}{ 8}\)

Note:

This is operator "3.27" from ...

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex  

2

New Number: 5.125 |  AESZ:  |  Superseeker: 229 10128562/3  |  Hash: ce147b64cc67dee1204a2d16f6ac4210  

Degree: 5

\(\theta^4-x\left(1217\theta^4+2050\theta^3+1437\theta^2+412\theta+44\right)+2^{5} x^{2}(\theta+1)(4550\theta^3-186\theta^2-899\theta-171)-2^{8} x^{3}\left(18484\theta^4+3192\theta^3+1005\theta^2+1107\theta+258\right)+2^{14} x^{4}(2\theta+1)(268\theta^3+414\theta^2+267\theta+65)-2^{20} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 44, 14532, 7508960, 4749338020, ...
--> OEIS
Normalized instanton numbers (n0=1): 229, 18542, 10128562/3, 938391582, 323686899951, ... ; Common denominator:...

Discriminant

\(-(z-1)(1024z^2-1088z+1)(-1+64z)^2\)

Local exponents

\(0\)\(\frac{ 17}{ 32}-\frac{ 3}{ 8}\sqrt{ 2}\)\(\frac{ 1}{ 64}\)\(1\)\(\frac{ 17}{ 32}+\frac{ 3}{ 8}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(4\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

B-Incarnation as fibre product 62211- x 362--1

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex  

3

New Number: 5.47 |  AESZ: 246  |  Superseeker: -4/5 -108/5  |  Hash: f51a0c39f9179dc6a561b9afb6f9d85f  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(12\theta^4+48\theta^3+49\theta^2+25\theta+5\right)-2^{4} x^{2}\left(544\theta^4+1792\theta^3+2444\theta^2+1580\theta+405\right)+2^{9} x^{3}\left(112\theta^4+960\theta^3+2306\theta^2+2130\theta+685\right)+2^{12} x^{4}\left(144\theta^4+768\theta^3+1308\theta^2+924\theta+235\right)+2^{20} x^{5}\left((\theta+1)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 4, 44, 400, 5356, ...
--> OEIS
Normalized instanton numbers (n0=1): -4/5, 22/5, -108/5, 694/5, -1040, ... ; Common denominator:...

Discriminant

\((1+16z)(16z+5)^2(16z-1)^2\)

Local exponents

\(-\frac{ 5}{ 16}\)\(-\frac{ 1}{ 16}\)\(0\)\(\frac{ 1}{ 16}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(\frac{ 1}{ 2}\)\(1\)
\(3\)\(1\)\(0\)\(\frac{ 1}{ 2}\)\(1\)
\(4\)\(2\)\(0\)\(1\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to Operator AESZ 247/5.48

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex  

4

New Number: 5.4 |  AESZ: 21  |  Superseeker: 8/5 152/5  |  Hash: 42a2bc0f0ee2a405ede956176c95721f  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(36\theta^4+84\theta^3+72\theta^2+30\theta+5\right)-2^{4} x^{2}\left(181\theta^4+268\theta^3+71\theta^2-70\theta-35\right)+2^{8} x^{3}(\theta+1)(37\theta^3+248\theta^2+375\theta+165)+2^{10} x^{4}\left(39\theta^4+198\theta^3+331\theta^2+232\theta+59\right)+2^{15} x^{5}\left((\theta+1)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 4, 44, 688, 13036, ...
--> OEIS
Normalized instanton numbers (n0=1): 8/5, 57/10, 152/5, 253, 11552/5, ... ; Common denominator:...

Discriminant

\((4z+1)(32z-1)(4z-1)(8z+5)^2\)

Local exponents

\(-\frac{ 5}{ 8}\)\(-\frac{ 1}{ 4}\)\(0\)\(\frac{ 1}{ 32}\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(4\)\(2\)\(0\)\(2\)\(2\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to
Operator AESZ 71/5.11

A-Incarnation: (2,0),(02),(1,1),(1,1),(1,1) intersection in $P^4 \times P^4$

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex  

5

New Number: 15.4 |  AESZ:  |  Superseeker: 52/5 13436/5  |  Hash: 2306e85a3af0a97d616dedf03cc93f69  

Degree: 15

\(5^{2} \theta^4-2^{2} 5 x\left(524\theta^4+56\theta^3+83\theta^2+55\theta+15\right)+2^{4} x^{2}\left(122784\theta^4+39552\theta^3+60584\theta^2+42560\theta+9895\right)-2^{8} x^{3}\left(851424\theta^4+544704\theta^3+819724\theta^2+563860\theta+144605\right)+2^{13} x^{4}\left(1949840\theta^4+2047744\theta^3+3062224\theta^2+2155304\theta+617905\right)-2^{18} x^{5}\left(3117952\theta^4+4806720\theta^3+7335648\theta^2+5468420\theta+1717063\right)+2^{22} x^{6}\left(7179524\theta^4+15086448\theta^3+24112808\theta^2+19319920\theta+6533401\right)-2^{26} x^{7}\left(12098492\theta^4+32868584\theta^3+56087648\theta^2+48438116\theta+17467537\right)+2^{31} x^{8}\left(7508036\theta^4+25345280\theta^3+46719420\theta^2+43397656\theta+16591239\right)-2^{38} x^{9}\left(856369\theta^4+3481940\theta^3+6970670\theta^2+6938899\theta+2800514\right)+2^{42} x^{10}\left(568775\theta^4+2715196\theta^3+5906890\theta^2+6274274\theta+2662654\right)-2^{46} x^{11}\left(269591\theta^4+1478382\theta^3+3484287\theta^2+3929620\theta+1745534\right)+2^{51} x^{12}\left(44091\theta^4+272424\theta^3+691403\theta^2+822862\theta+380404\right)-2^{57} x^{13}\left(2349\theta^4+16068\theta^3+43548\theta^2+54271\theta+25924\right)+2^{63} x^{14}\left(73\theta^4+544\theta^3+1559\theta^2+2017\theta+988\right)-2^{69} x^{15}\left((\theta+2)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 12, 44, -3792, -207124, ...
--> OEIS
Normalized instanton numbers (n0=1): 52/5, 115, 13436/5, 89632, 18465296/5, ... ; Common denominator:...

Discriminant

\(-(-1+32z)(256z^2-48z+1)^2(512z^2-128z+5)^2(64z-1)^3(16z-1)^3\)

Local exponents

\(0\)\(\frac{ 1}{ 64}\)\(\frac{ 3}{ 32}-\frac{ 1}{ 32}\sqrt{ 5}\)\(\frac{ 1}{ 32}\)\(\frac{ 1}{ 8}-\frac{ 1}{ 32}\sqrt{ 6}\)\(\frac{ 1}{ 16}\)\(\frac{ 3}{ 32}+\frac{ 1}{ 32}\sqrt{ 5}\)\(\frac{ 1}{ 8}+\frac{ 1}{ 32}\sqrt{ 6}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(2\)
\(0\)\(2\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(0\)\(\frac{ 1}{ 2}\)\(1\)\(2\)
\(0\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(3\)\(0\)\(\frac{ 1}{ 2}\)\(3\)\(2\)
\(0\)\(5\)\(1\)\(2\)\(4\)\(0\)\(1\)\(4\)\(2\)

Note:

This is operator "15.4" from ...

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex