Summary

You searched for: sol=3996751

Your search produced exactly one match

1

New Number: 5.22 |  AESZ: 193  |  Superseeker: 129/7 41441/7  |  Hash: 44e6fc2823d5ff31e66059ba6b37f2ae  

Degree: 5

\(7^{2} \theta^4-7 x\left(1135\theta^4+2204\theta^3+1683\theta^2+581\theta+77\right)+x^{2}\left(28723\theta^4+40708\theta^3+13260\theta^2-1337\theta-896\right)-x^{3}\left(32126\theta^4+38514\theta^3+26511\theta^2+10731\theta+1806\right)+7 11 x^{4}\left(130\theta^4+254\theta^3+192\theta^2+65\theta+8\right)+11^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 11, 559, 42923, 3996751, ...
--> OEIS
Normalized instanton numbers (n0=1): 129/7, 1557/7, 41441/7, 1594332/7, 75470601/7, ... ; Common denominator:...

Discriminant

\((z^3+84z^2-159z+1)(-7+11z)^2\)

Local exponents

≈\(-85.852157\)\(0\) ≈\(0.00631\)\(\frac{ 7}{ 11}\) ≈\(1.845846\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to Operator AESZ 198/5.25

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