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You searched for: sol=378

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1

New Number: 13.6 |  AESZ:  |  Superseeker: 2 421/9  |  Hash: 679aa37a05aafe03e8d68785d566fcfb  

Degree: 13

\(\theta^4-x\left(217\theta^4+178\theta^3+178\theta^2+89\theta+18\right)+x^{2}\left(6192+24334\theta+39795\theta^2+33324\theta^3+20643\theta^4\right)-2^{3} x^{3}\left(139307\theta^4+333558\theta^3+457560\theta^2+315505\theta+89244\right)+2^{4} x^{4}\left(2283535\theta^4+7259062\theta^3+11103058\theta^2+8192571\theta+2419362\right)-2^{6} 3 x^{5}\left(3630237\theta^4+14551206\theta^3+23954402\theta^2+17624013\theta+4953960\right)+2^{6} 3^{2} x^{6}\left(9379387\theta^4+48172928\theta^3+74157721\theta^2+31932048\theta-1833876\right)+2^{9} 3^{5} x^{7}\left(495945\theta^4+2307886\theta^3+6892788\theta^2+10676039\theta+5452406\right)-2^{12} 3^{4} x^{8}\left(5269994\theta^4+31826568\theta^3+83327461\theta^2+106595346\theta+49104855\right)+2^{15} 3^{7} x^{9}\left(129774\theta^4+976140\theta^3+2673571\theta^2+3442327\theta+1597000\right)+2^{18} 3^{10} x^{10}(\theta+1)(6759\theta^3+40481\theta^2+97855\theta+79397)-2^{21} 3^{9} x^{11}(\theta+1)(\theta+2)(29107\theta^2+160713\theta+251822)-2^{27} 3^{12} x^{12}(\theta+3)(\theta+2)(\theta+1)(17\theta+4)+2^{29} 3^{15} 5 x^{13}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 18, 378, 8280, 187434, ...
--> OEIS
Normalized instanton numbers (n0=1): 2, -3/2, 421/9, -519/2, 285, ... ; Common denominator:...

Discriminant

\((16z-1)(19440z^3-2187z^2+81z-1)(24z-1)^2(648z^2-48z+1)^2(8z+1)^3\)

Local exponents

\(-\frac{ 1}{ 8}\)\(0\) ≈\(0.032165-0.005771I\) ≈\(0.032165+0.005771I\)\(\frac{ 1}{ 27}-\frac{ 1}{ 108}\sqrt{ 2}I\)\(\frac{ 1}{ 27}+\frac{ 1}{ 108}\sqrt{ 2}I\)\(\frac{ 1}{ 24}\) ≈\(0.04817\)\(\frac{ 1}{ 16}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(2\)
\(\frac{ 3}{ 2}\)\(0\)\(1\)\(1\)\(3\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(3\)
\(2\)\(0\)\(2\)\(2\)\(4\)\(4\)\(1\)\(2\)\(2\)\(4\)

Note:

This is operator "13.6" from ...

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2

New Number: 6.7 |  AESZ:  |  Superseeker: -9 217/3  |  Hash: 9492f991c909a6774f5546668ff53b6a  

Degree: 6

\(\theta^4-3 x\left(42\theta^4+84\theta^3+77\theta^2+35\theta+6\right)+3^{3} x^{2}\left(291\theta^4+1164\theta^3+1747\theta^2+1166\theta+264\right)-2^{2} 3^{5} x^{3}\left(360\theta^4+2160\theta^3+4553\theta^2+3939\theta+1035\right)+2^{3} 3^{8} x^{4}\left(204\theta^4+1632\theta^3+4449\theta^2+4740\theta+1400\right)-2^{4} 3^{11} x^{5}(16\theta^2+80\theta+35)(2\theta+5)^2+2^{4} 3^{14} x^{6}(2\theta+11)(2\theta+7)(2\theta+5)(2\theta+1)\)

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Coefficients of the holomorphic solution: 1, 18, 378, 8820, 266490, ...
--> OEIS
Normalized instanton numbers (n0=1): -9, 18, 217/3, -9, -146079, ... ; Common denominator:...

Discriminant

\((27z-1)(34992z^3-1944z^2+27z-1)(-1+36z)^2\)

Local exponents

\(0\) ≈\(0.002095-0.023494I\) ≈\(0.002095+0.023494I\)\(\frac{ 1}{ 36}\)\(\frac{ 1}{ 27}\) ≈\(0.051365\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(\frac{ 5}{ 2}\)
\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(\frac{ 7}{ 2}\)
\(0\)\(2\)\(2\)\(1\)\(2\)\(2\)\(\frac{ 11}{ 2}\)

Note:

This is operator "6.7" from ...

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3

New Number: 8.15 |  AESZ: 178  |  Superseeker: 18 9799/3  |  Hash: e748913f322a008ae5c350f96f1cd860  

Degree: 8

\(\theta^4-3 x(3\theta^2+3\theta+1)(17\theta^2+17\theta+6)+3^{3} x^{2}\left(217\theta^4+1732\theta^3+2441\theta^2+1418\theta+336\right)+2^{3} 3^{6} x^{3}\left(51\theta^4-306\theta^3-934\theta^2-717\theta-204\right)-2^{4} 3^{8} x^{4}\left(289\theta^4+578\theta^3-1310\theta^2-1599\theta-570\right)+2^{6} 3^{11} x^{5}\left(51\theta^4+510\theta^3+290\theta^2-29\theta-64\right)+2^{6} 3^{13} x^{6}\left(217\theta^4-864\theta^3-1453\theta^2-864\theta-156\right)-2^{9} 3^{16} x^{7}(3\theta^2+3\theta+1)(17\theta^2+17\theta+6)+2^{12} 3^{20} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 18, 378, 6552, 21546, ...
--> OEIS
Normalized instanton numbers (n0=1): 18, -423/2, 9799/3, -150003/2, 1914237, ... ; Common denominator:...

Discriminant

\((1728z^2-72z+1)(2187z^2-81z+1)(-1+1944z^2)^2\)

Local exponents

\(-\frac{ 1}{ 108}\sqrt{ 6}\)\(0\)\(\frac{ 1}{ 54}-\frac{ 1}{ 162}\sqrt{ 3}I\)\(\frac{ 1}{ 54}+\frac{ 1}{ 162}\sqrt{ 3}I\)\(\frac{ 1}{ 48}-\frac{ 1}{ 144}\sqrt{ 3}I\)\(\frac{ 1}{ 48}+\frac{ 1}{ 144}\sqrt{ 3}I\)\(\frac{ 1}{ 108}\sqrt{ 6}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(3\)\(0\)\(1\)\(1\)\(1\)\(1\)\(3\)\(1\)
\(4\)\(0\)\(2\)\(2\)\(2\)\(2\)\(4\)\(1\)

Note:

Hadamard product $d \ast g$. This operator has a second MUM-point at infinity. It can be reduced to an operator of degree 4 with a single MUM-point defined over $Q(\sqrt{?})$.

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4

New Number: 9.7 |  AESZ:  |  Superseeker: 9 2564/3  |  Hash: 9bb7a7f3a3d5f66018396173696c194c  

Degree: 9

\(\theta^4+3 x\left(93\theta^4+42\theta^3+49\theta^2+28\theta+6\right)+2^{2} 3^{3} x^{2}\left(307\theta^4+328\theta^3+401\theta^2+230\theta+53\right)+2^{2} 3^{5} x^{3}\left(2268\theta^4+4128\theta^3+5443\theta^2+3525\theta+932\right)+2^{4} 3^{7} x^{4}\left(2588\theta^4+6880\theta^3+10145\theta^2+7398\theta+2167\right)+2^{6} 3^{9} x^{5}\left(1897\theta^4+6694\theta^3+11167\theta^2+9015\theta+2853\right)+2^{8} 3^{11} x^{6}\left(895\theta^4+3912\theta^3+7309\theta^2+6408\theta+2150\right)+2^{8} 3^{13} x^{7}\left(1048\theta^4+5360\theta^3+10939\theta^2+10155\theta+3534\right)+2^{10} 3^{15} x^{8}(\theta+1)(172\theta^3+804\theta^2+1295\theta+699)+2^{12} 3^{18} x^{9}(\theta+2)(\theta+1)(2\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, -18, 378, -8676, 213354, ...
--> OEIS
Normalized instanton numbers (n0=1): 9, -72, 2564/3, -12924, 228024, ... ; Common denominator:...

Discriminant

\((27z+1)(432z^2+36z+1)(36z+1)^2(648z^2+72z+1)^2\)

Local exponents

\(-\frac{ 1}{ 18}-\frac{ 1}{ 36}\sqrt{ 2}\)\(-\frac{ 1}{ 24}-\frac{ 1}{ 72}\sqrt{ 3}I\)\(-\frac{ 1}{ 24}+\frac{ 1}{ 72}\sqrt{ 3}I\)\(-\frac{ 1}{ 27}\)\(-\frac{ 1}{ 36}\)\(-\frac{ 1}{ 18}+\frac{ 1}{ 36}\sqrt{ 2}\)\(0\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(0\)\(\frac{ 3}{ 2}\)
\(3\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)\(3\)\(0\)\(\frac{ 3}{ 2}\)
\(4\)\(2\)\(2\)\(2\)\(1\)\(4\)\(0\)\(2\)

Note:

This is operator "9.7" from ...

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