Summary

You searched for: sol=359800

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1

New Number: 5.113 |  AESZ: 403  |  Superseeker: -29/5 -1481/5  |  Hash: 492c8a69e87d470c87b9557834f0fc5b  

Degree: 5

\(5^{2} \theta^4+5 x\left(487\theta^4+878\theta^3+709\theta^2+270\theta+40\right)+2^{5} x^{2}\left(1013\theta^4+2639\theta^3+2943\theta^2+1520\theta+280\right)-2^{8} x^{3}\left(2169\theta^4+14880\theta^3+30789\theta^2+22440\theta+5240\right)-2^{12} x^{4}(2\theta+1)(518\theta^3+2397\theta^2+2940\theta+1048)-2^{16} 3 x^{5}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, -8, 216, -8000, 359800, ...
--> OEIS
Normalized instanton numbers (n0=1): -29/5, 229/5, -1481/5, 43173/5, -155267, ... ; Common denominator:...

Discriminant

\(-(27z+1)(1024z^2-64z-1)(5+16z)^2\)

Local exponents

\(-\frac{ 5}{ 16}\)\(-\frac{ 1}{ 27}\)\(\frac{ 1}{ 32}-\frac{ 1}{ 32}\sqrt{ 2}\)\(0\)\(\frac{ 1}{ 32}+\frac{ 1}{ 32}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 2}{ 3}\)
\(3\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 4}{ 3}\)
\(4\)\(2\)\(2\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.113" from ...

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