Summary

You searched for: sol=3510

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1

New Number: 5.102 |  AESZ: 352  |  Superseeker: 1 -12  |  Hash: fc8b141522720827b1dd2cd28a232c1b  

Degree: 5

\(\theta^4-x\left(70\theta^4+86\theta^3+77\theta^2+34\theta+6\right)+3 x^{2}\left(675\theta^4+1602\theta^3+1933\theta^2+1130\theta+258\right)-2^{2} 3^{3} x^{3}\left(271\theta^4+888\theta^3+1259\theta^2+831\theta+207\right)+2^{2} 3^{5} x^{4}\left(212\theta^4+808\theta^3+1189\theta^2+773\theta+186\right)-2^{4} 3^{7} x^{5}(4\theta+3)(\theta+1)^2(4\theta+5)\)

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Coefficients of the holomorphic solution: 1, 6, 54, 492, 3510, ...
--> OEIS
Normalized instanton numbers (n0=1): 1, -7/8, -12, -131/4, 90, ... ; Common denominator:...

Discriminant

\(-(16z-1)(432z^2-36z+1)(-1+9z)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 24}-\frac{ 1}{ 72}\sqrt{ 3}I\)\(\frac{ 1}{ 24}+\frac{ 1}{ 72}\sqrt{ 3}I\)\(\frac{ 1}{ 16}\)\(\frac{ 1}{ 9}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 3}{ 4}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(3\)\(1\)
\(0\)\(2\)\(2\)\(2\)\(4\)\(\frac{ 5}{ 4}\)

Note:

This is operator "5.102" from ...

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