Summary

You searched for: sol=34944

Your search produced exactly one match

1

New Number: 8.14 |  AESZ: 176  |  Superseeker: 24 15448/3  |  Hash: e2a40a57f7e88dba6655d936b4abe327  

Degree: 8

\(\theta^4-2^{2} x(3\theta^2+3\theta+1)(17\theta^2+17\theta+6)+2^{5} x^{2}\left(325\theta^4+2164\theta^3+3053\theta^2+1778\theta+420\right)+2^{10} 3^{2} x^{3}\left(51\theta^4-306\theta^3-934\theta^2-717\theta-204\right)-2^{14} 3^{2} x^{4}\left(397\theta^4+794\theta^3-1454\theta^2-1851\theta-666\right)+2^{18} 3^{4} x^{5}\left(51\theta^4+510\theta^3+290\theta^2-29\theta-64\right)+2^{21} 3^{4} x^{6}\left(325\theta^4-864\theta^3-1489\theta^2-864\theta-144\right)-2^{26} 3^{6} x^{7}(3\theta^2+3\theta+1)(17\theta^2+17\theta+6)+2^{32} 3^{8} x^{8}\left((\theta+1)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 24, 840, 34944, 1618344, ...
--> OEIS
Normalized instanton numbers (n0=1): 24, -509/2, 15448/3, -128530, 3746624, ... ; Common denominator:...

Discriminant

\((72z-1)(36z-1)(64z-1)(32z-1)(48z-1)^2(48z+1)^2\)

Local exponents

\(-\frac{ 1}{ 48}\)\(0\)\(\frac{ 1}{ 72}\)\(\frac{ 1}{ 64}\)\(\frac{ 1}{ 48}\)\(\frac{ 1}{ 36}\)\(\frac{ 1}{ 32}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(3\)\(0\)\(1\)\(1\)\(3\)\(1\)\(1\)\(1\)
\(4\)\(0\)\(2\)\(2\)\(4\)\(2\)\(2\)\(1\)

Note:

Hadamard product $d \ast g$. This operator has a second MUM-point at infinity with the same instanton numbers. It
can be reduced to an operator of degree 4 with a single MUM-point defined over $Q(\sqrt{?})$.

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex