Summary

You searched for: sol=3474

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1

New Number: 8.51 |  AESZ:  |  Superseeker: 58/43 1024/43  |  Hash: 85b9064701880ae8e0518e47cff1b030  

Degree: 8

\(43^{2} \theta^4-43 x\theta(142\theta^3+890\theta^2+574\theta+129)-x^{2}\left(647269\theta^4+2441818\theta^3+3538503\theta^2+2423953\theta+650848\right)-x^{3}\left(7200000\theta^4+34423908\theta^3+65337898\theta^2+57379329\theta+19251960\right)-x^{4}\left(37610765\theta^4+220029964\theta^3+499781264\theta^2+511393545\theta+194039928\right)-2 x^{5}(\theta+1)(54978121\theta^3+324737370\theta^2+665066226\theta+466789876)-x^{6}(\theta+1)(\theta+2)(185181547\theta^2+915931425\theta+1176131796)-2^{2} 3 101 x^{7}(\theta+3)(\theta+2)(\theta+1)(138979\theta+413408)-2^{2} 3^{2} 5^{2} 7 101^{2} x^{8}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 0, 22, 204, 3474, ...
--> OEIS
Normalized instanton numbers (n0=1): 58/43, 211/43, 1024/43, 7544/43, 64880/43, ... ; Common denominator:...

Discriminant

\(-(7z+1)(25z-1)(2z+1)^2(101z+43)^2(3z+1)^2\)

Local exponents

\(-\frac{ 1}{ 2}\)\(-\frac{ 43}{ 101}\)\(-\frac{ 1}{ 3}\)\(-\frac{ 1}{ 7}\)\(0\)\(\frac{ 1}{ 25}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(\frac{ 1}{ 3}\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(0\)\(1\)\(2\)
\(\frac{ 2}{ 3}\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(0\)\(1\)\(3\)
\(1\)\(4\)\(1\)\(2\)\(0\)\(2\)\(4\)

Note:

This is operator "8.51" from ...

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