Summary

You searched for: sol=29500/81

Your search produced exactly one match

1

New Number: 6.24 |  AESZ:  |  Superseeker: 1/3 5/3  |  Hash: aebe18b25bf886c4483ce54370c0fcbe  

Degree: 6

\(3^{6} \theta^4+3^{5} x\left(7\theta^2+7\theta+2\right)-3^{4} x^{2}\left(1095\theta^4+4380\theta^3+7227\theta^2+5694\theta+1760\right)-2 3^{3} x^{3}(\theta+2)(\theta+1)(4165\theta^2+12495\theta+11148)+2^{2} 3^{2} x^{4}(47961\theta^2+191844\theta+148643)(\theta+2)^2+2^{3} 3^{2} 5 7 17 73 x^{5}(\theta+1)(\theta+2)(\theta+3)(\theta+4)-2^{5} 5^{2} 7^{2} 17^{2} x^{6}(\theta+5)(\theta+4)(\theta+2)(\theta+1)\)

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Coefficients of the holomorphic solution: 1, -2/3, 112/9, -8/27, 29500/81, ...
--> OEIS
Normalized instanton numbers (n0=1): 1/3, 5/6, 5/3, 19/3, 29, ... ; Common denominator:...

Discriminant

\(-(7z-3)(34z-3)(17z+3)(20z+3)(10z-3)(14z+3)\)

Local exponents

\(-\frac{ 3}{ 14}\)\(-\frac{ 3}{ 17}\)\(-\frac{ 3}{ 20}\)\(0\)\(\frac{ 3}{ 34}\)\(\frac{ 3}{ 10}\)\(\frac{ 3}{ 7}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(2\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(4\)
\(2\)\(2\)\(2\)\(0\)\(2\)\(2\)\(2\)\(5\)

Note:

This is operator "6.24" from ...

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