Summary

You searched for: sol=2860801391700

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1

New Number: 5.115 |  AESZ: 413  |  Superseeker: -3843 -2715123387  |  Hash: 2cc16ba9e49744872ae72bfd6b36d064  

Degree: 5

\(\theta^4-3^{2} x\left(2835\theta^4-162\theta^3+261\theta^2+342\theta+68\right)+2^{2} 3^{9} x^{2}\left(3024\theta^4+918\theta^3+1977\theta^2+606\theta+64\right)-2^{2} 3^{16} x^{3}\left(5832\theta^4+7128\theta^3+7137\theta^2+3087\theta+524\right)+2^{4} 3^{25} x^{4}(2\theta+1)(72\theta^3+144\theta^2+121\theta+36)-2^{6} 3^{31} x^{5}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 612, 836244, 1455469200, 2860801391700, ...
--> OEIS
Normalized instanton numbers (n0=1): -3843, -9668061/4, -2715123387, -3984527414448, -6798579266503881, ... ; Common denominator:...

Discriminant

\(-(-1+2187z)(8748z-1)^2(2916z-1)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 8748}\)\(\frac{ 1}{ 2916}\)\(\frac{ 1}{ 2187}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(\frac{ 2}{ 3}\)
\(0\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(\frac{ 4}{ 3}\)
\(0\)\(4\)\(1\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.115" from ...

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