Summary

You searched for: sol=282366

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1

New Number: 11.10 |  AESZ:  |  Superseeker: 307/31 30366/31  |  Hash: 4af67003a52ef978f182204bfaff3b67  

Degree: 11

\(31^{2} \theta^4-31 x\theta(37\theta^3+3404\theta^2+2167\theta+465)-x^{2}\left(3584242\theta^4+13193680\theta^3+15543050\theta^2+9592175\theta+2490912\right)-3^{2} x^{3}\left(19107317\theta^4+73205086\theta^3+112285993\theta^2+86123611\theta+26445852\right)-3 x^{4}\left(1372729742\theta^4+6047894734\theta^3+11016338393\theta^2+9650491725\theta+3283335324\right)-x^{5}\left(61079790533\theta^4+312026249948\theta^3+649293087145\theta^2+630130831252\theta+231606447564\right)-2 3^{2} x^{6}\left(33534165907\theta^4+196973375042\theta^3+458528416805\theta^2+484791515686\theta+189712671726\right)-3^{2} 7 x^{7}\left(64606565117\theta^4+431259053450\theta^3+1107908854519\theta^2+1261805762830\theta+520567245048\right)-3^{4} 7^{2} x^{8}(\theta+1)(4683541363\theta^3+30431977551\theta^2+68128269606\theta+51768680224)-2^{2} 3^{3} 7^{3} x^{9}(\theta+1)(\theta+2)(1489780280\theta^2+7942046183\theta+10944040794)-2^{2} 3^{4} 7^{4} 53 x^{10}(\theta+3)(\theta+2)(\theta+1)(2336627\theta+7400894)-2^{5} 3^{3} 7^{5} 19 53^{2} 97 x^{11}(\theta+1)(\theta+2)(\theta+3)(\theta+4)\)

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Coefficients of the holomorphic solution: 1, 0, 162, 5472, 282366, ...
--> OEIS
Normalized instanton numbers (n0=1): 307/31, 1814/31, 30366/31, 639686/31, 17126962/31, ... ; Common denominator:...

Discriminant

\(-(8z+1)(679z^2+74z-1)(57z^2+15z+1)(7z+1)^2(2226z^2+555z+31)^2\)

Local exponents

\(-\frac{ 185}{ 1484}-\frac{ 1}{ 4452}\sqrt{ 32001}\)\(-\frac{ 1}{ 7}\)\(-\frac{ 5}{ 38}-\frac{ 1}{ 114}\sqrt{ 3}I\)\(-\frac{ 5}{ 38}+\frac{ 1}{ 114}\sqrt{ 3}I\)\(-\frac{ 1}{ 8}\)\(-\frac{ 37}{ 679}-\frac{ 32}{ 679}\sqrt{ 2}\)\(-\frac{ 185}{ 1484}+\frac{ 1}{ 4452}\sqrt{ 32001}\)\(0\)\(-\frac{ 37}{ 679}+\frac{ 32}{ 679}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(2\)
\(3\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)\(1\)\(3\)\(0\)\(1\)\(3\)
\(4\)\(1\)\(2\)\(2\)\(2\)\(2\)\(4\)\(0\)\(2\)\(4\)

Note:

This is operator "11.10" from ...

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