Summary

You searched for: sol=25299

Your search produced exactly one match

1

New Number: 5.20 |  AESZ: 186  |  Superseeker: 49/19 1761/19  |  Hash: b3d164f22d02de1efcd62d3aa9ab5ce4  

Degree: 5

\(19^{2} \theta^4-19 x\left(700\theta^4+1238\theta^3+999\theta^2+380\theta+57\right)-x^{2}\left(64745\theta^4+368006\theta^3+609133\theta^2+412756\theta+102258\right)+3^{3} x^{3}\left(6397\theta^4+12198\theta^3-11923\theta^2-27360\theta-11286\right)+3^{6} x^{4}\left(64\theta^4+1154\theta^3+2425\theta^2+1848\theta+486\right)-3^{11} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 3, 51, 1029, 25299, ...
--> OEIS
Normalized instanton numbers (n0=1): 49/19, 252/19, 1761/19, 18990/19, 246159/19, ... ; Common denominator:...

Discriminant

\(-(z+1)(243z^2+35z-1)(-19+27z)^2\)

Local exponents

\(-1\)\(-\frac{ 35}{ 486}-\frac{ 13}{ 486}\sqrt{ 13}\)\(0\)\(-\frac{ 35}{ 486}+\frac{ 13}{ 486}\sqrt{ 13}\)\(\frac{ 19}{ 27}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(3\)\(1\)
\(2\)\(2\)\(0\)\(2\)\(4\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to Operator AESZ 187/5.21

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