Summary

You searched for: sol=2464

Your search produced exactly one match

1

New Number: 6.20 |  AESZ:  |  Superseeker: 0 -1/3  |  Hash: 5169c67af7361bf7e6467dabea9612bd  

Degree: 6

\(\theta^4+x\left(11\theta+26\theta^3+2+13\theta^4+24\theta^2\right)-x^{2}(141\theta^2+282\theta+296)(\theta+1)^2-2 x^{3}(\theta+2)(\theta+1)(407\theta^2+1221\theta+654)+2^{2} 7 x^{4}(\theta+3)(\theta+1)(389\theta^2+1556\theta+1460)-2^{3} 3 7^{2} x^{5}(\theta+4)(\theta+1)(29\theta^2+145\theta+166)+2^{5} 3 7^{3} x^{6}(\theta+5)(\theta+4)(\theta+2)(\theta+1)\)

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Coefficients of the holomorphic solution: 1, -2, 28, -224, 2464, ...
--> OEIS
Normalized instanton numbers (n0=1): 0, 1/2, -1/3, -1, -2, ... ; Common denominator:...

Discriminant

\((-1+2z)(4z-1)(21z^2-9z+1)(1+14z)^2\)

Local exponents

\(-\frac{ 1}{ 14}\)\(0\)\(\frac{ 3}{ 14}-\frac{ 1}{ 42}\sqrt{ 3}I\)\(\frac{ 3}{ 14}+\frac{ 1}{ 42}\sqrt{ 3}I\)\(\frac{ 1}{ 4}\)\(\frac{ 1}{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)\(1\)\(1\)\(2\)
\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)\(1\)\(1\)\(4\)
\(1\)\(0\)\(2\)\(2\)\(2\)\(2\)\(5\)

Note:

This is operator "6.20" from ...

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