Summary

You searched for: sol=23120

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1

New Number: 5.88 |  AESZ: 324  |  Superseeker: 148/11 44108/11  |  Hash: 7f84d776cf00ff399b20865542185f87  

Degree: 5

\(11^{2} \theta^4-2^{2} 11 x\left(432\theta^4+624\theta^3+477\theta^2+165\theta+22\right)+2^{5} x^{2}\left(12944\theta^4+4736\theta^3-15491\theta^2-12914\theta-2860\right)-2^{4} 5 x^{3}\left(10688\theta^4-114048\theta^3-159132\theta^2-83028\theta-15455\right)-2^{11} 5^{2} x^{4}(2\theta+1)(4\theta+3)(76\theta^2+189\theta+125)+2^{14} 5^{3} x^{5}(2\theta+1)(4\theta+3)(4\theta+5)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 8, 360, 23120, 1796200, ...
--> OEIS
Normalized instanton numbers (n0=1): 148/11, 2044/11, 44108/11, 1459636/11, 60212712/11, ... ; Common denominator:...

Discriminant

\((5120z^3-512z^2-128z+1)(-11+160z)^2\)

Local exponents

≈\(-0.120643\)\(0\) ≈\(0.007599\)\(\frac{ 11}{ 160}\) ≈\(0.213044\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 3}{ 4}\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(\frac{ 5}{ 4}\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.88" from ...

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