Summary

You searched for: sol=198416

Your search produced exactly one match

1

New Number: 5.57 |  AESZ: 263  |  Superseeker: 1312 58156704  |  Hash: 2157fe92de97f7b684b3cbd7b8bdf280  

Degree: 5

\(\theta^4+2^{4} x\left(464\theta^4-32\theta^3+76\theta^2+92\theta+21\right)+2^{15} x^{2}\left(608\theta^4+152\theta^3+450\theta^2+131\theta+5\right)+2^{22} x^{3}\left(5584\theta^4+6144\theta^3+6852\theta^2+2808\theta+471\right)+2^{34} 5 x^{4}\left(136\theta^4+320\theta^3+341\theta^2+181\theta+39\right)+2^{46} 5^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -336, 198416, -142318848, 112152177936, ...
--> OEIS
Normalized instanton numbers (n0=1): 1312, -211968, 58156704, -19819112104, 7519377878624, ... ; Common denominator:...

Discriminant

\((1+256z)(1024z+1)^2(2560z+1)^2\)

Local exponents

\(-\frac{ 1}{ 256}\)\(-\frac{ 1}{ 1024}\)\(-\frac{ 1}{ 2560}\)\(0\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(0\)\(1\)
\(1\)\(1\)\(3\)\(0\)\(1\)
\(2\)\(1\)\(4\)\(0\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to Operator AESZ 262/5.56

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