Summary

You searched for: sol=196000

Your search produced exactly one match

1

New Number: 5.29 |  AESZ: 208  |  Superseeker: 274/7 281388/7  |  Hash: f1d6dfa8a5cdcc2513dfca4243565b2f  

Degree: 5

\(7^{2} \theta^4-2 7 x\left(1056\theta^4+1884\theta^3+1397\theta^2+455\theta+56\right)+2^{2} 3 x^{2}\left(22760\theta^4+13672\theta^3-22537\theta^2-18116\theta-3584\right)-2^{4} x^{3}\left(53312\theta^4-162120\theta^3-195172\theta^2-78561\theta-11130\right)-2^{6} 19 x^{4}(1189\theta^2+2533\theta+1646)(2\theta+1)^2+2^{11} 19^{2} x^{5}(2\theta+1)^2(2\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, 16, 1440, 196000, 32418400, ...
--> OEIS
Normalized instanton numbers (n0=1): 274/7, 6115/7, 281388/7, 2815228, 1699166270/7, ... ; Common denominator:...

Discriminant

\((4z+1)(512z^2-284z+1)(-7+76z)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(0\)\(\frac{ 71}{ 256}-\frac{ 17}{ 256}\sqrt{ 17}\)\(\frac{ 7}{ 76}\)\(\frac{ 71}{ 256}+\frac{ 17}{ 256}\sqrt{ 17}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(\frac{ 3}{ 2}\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.29" from ...

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